General
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Physics-

The value of force constant between the applied elastic force F and displacement will be

Physics-General

  1. fraction numerator square root of 3 over denominator 2 end fraction    
  2. square root of 3    
  3. fraction numerator 1 over denominator square root of 3 end fraction    
  4. fraction numerator 1 over denominator 2 end fraction    

    Answer:The correct answer is: fraction numerator 1 over denominator square root of 3 end fractionForce constant, K equals tan invisible function application 30 degree equals 1 divided by square root of 3

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    General
    physics-

    A copper rod of length L and radius ris suspended from the ceiling by one of its ends. What will be elongation of the rod due to its own weight when rho blank a n d blank Y are the density and Young’s modulus of the copper respectively?

    The weight of the rod can be assumed to act at its mid-point.
    Now, the mass of the rod is
    M equals V rho
    M equals A L rho
    Here, A equals a r e a blank o f blank c r o s s minus s e c t i o n s comma
    L= length of the rod.
    Now, we know that the Young’s modulus

    Y equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A bullet l blank end fraction blank left parenthesis H e r e comma blank L equals fraction numerator L over denominator 2 end fraction comma l equals e x t e n s i o n right parenthesis
    l equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A Y end fraction
    or l equals fraction numerator M g L over denominator 2 A Y end fraction
    On putting the value of M from Eq.(i), we get
    l equals fraction numerator A L rho bullet g L over denominator 2 A Y end fraction
    orl equals fraction numerator rho g L to the power of 2 end exponent over denominator 2 Y end fraction

    A copper rod of length L and radius ris suspended from the ceiling by one of its ends. What will be elongation of the rod due to its own weight when rho blank a n d blank Y are the density and Young’s modulus of the copper respectively?

    physics-General
    The weight of the rod can be assumed to act at its mid-point.
    Now, the mass of the rod is
    M equals V rho
    M equals A L rho
    Here, A equals a r e a blank o f blank c r o s s minus s e c t i o n s comma
    L= length of the rod.
    Now, we know that the Young’s modulus

    Y equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A bullet l blank end fraction blank left parenthesis H e r e comma blank L equals fraction numerator L over denominator 2 end fraction comma l equals e x t e n s i o n right parenthesis
    l equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A Y end fraction
    or l equals fraction numerator M g L over denominator 2 A Y end fraction
    On putting the value of M from Eq.(i), we get
    l equals fraction numerator A L rho bullet g L over denominator 2 A Y end fraction
    orl equals fraction numerator rho g L to the power of 2 end exponent over denominator 2 Y end fraction
    General
    physics-

    A student plots a graph from his reading on the determination of Young’s modulus of a metal wire but forgets to label. The quantities on X and Y axes may be respectively

    A student plots a graph from his reading on the determination of Young’s modulus of a metal wire but forgets to label. The quantities on X and Y axes may be respectively

    physics-General
    General
    physics-

    If the ratio of lengths, radii and Young’s modulus of steel and brass wires shown in the figure are a comma blank band c, respectively. The ratio between the increase in lengths of brass and steel wires would be

    Given, fraction numerator l subscript 1 end subscript over denominator l subscript 2 end subscript end fraction equals a comma fraction numerator r subscript 1 end subscript over denominator r subscript 2 end subscript end fraction equals b comma fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals c

    Let Young’s modulus of steel be Y subscript 1 end subscript, and that of brass be Y subscript 2 end subscript
    therefore Y subscript 1 end subscript equals fraction numerator F subscript 1 end subscript l subscript 1 end subscript over denominator A subscript 1 end subscript increment l subscript 1 end subscript end fraction (i)
    and Y subscript 2 end subscript equals fraction numerator F subscript 2 end subscript l subscript 2 end subscript over denominator A subscript 2 end subscript increment l subscript 2 end subscript end fraction(ii)
    Dividing Equation (i) by Equation (ii), we get
    fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals fraction numerator F subscript 1 end subscript. A subscript 2 end subscript. l subscript 1 end subscript. increment l subscript 2 end subscript over denominator F subscript 2 end subscript. A subscript 1 end subscript. l subscript 2 end subscript. increment l subscript 1 end subscript end fraction(iii)
    Force on steel wire from free body diagram
    T equals F subscript 1 end subscript equals left parenthesis 2 g right parenthesis Newton
    Force on brass wire from free body diagram
    F subscript 2 end subscript equals T subscript 1 end subscript superscript ´ ´ end superscript equals T plus 2 g equals 4 g Newton
    Now, putting the value of F subscript 1 end subscript comma F subscript 2 end subscript comma in Equation (iii), we get
    fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals open parentheses fraction numerator 2 g over denominator 4 g end fraction close parentheses. open parentheses fraction numerator pi r subscript 2 end subscript superscript 2 end superscript over denominator pi r subscript 1 end subscript superscript 2 end superscript end fraction close parentheses. open square brackets fraction numerator l subscript 1 end subscript over denominator l subscript 2 end subscript end fraction close square brackets. open parentheses fraction numerator increment l subscript 2 end subscript over denominator increment l subscript 1 end subscript end fraction close parentheses equals fraction numerator 1 over denominator 2 end fraction open parentheses fraction numerator 1 over denominator b subscript 2 end subscript end fraction close parentheses. a open parentheses fraction numerator increment l subscript 2 end subscript over denominator increment l subscript 1 end subscript end fraction close parentheses

    If the ratio of lengths, radii and Young’s modulus of steel and brass wires shown in the figure are a comma blank band c, respectively. The ratio between the increase in lengths of brass and steel wires would be

    physics-General
    Given, fraction numerator l subscript 1 end subscript over denominator l subscript 2 end subscript end fraction equals a comma fraction numerator r subscript 1 end subscript over denominator r subscript 2 end subscript end fraction equals b comma fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals c

    Let Young’s modulus of steel be Y subscript 1 end subscript, and that of brass be Y subscript 2 end subscript
    therefore Y subscript 1 end subscript equals fraction numerator F subscript 1 end subscript l subscript 1 end subscript over denominator A subscript 1 end subscript increment l subscript 1 end subscript end fraction (i)
    and Y subscript 2 end subscript equals fraction numerator F subscript 2 end subscript l subscript 2 end subscript over denominator A subscript 2 end subscript increment l subscript 2 end subscript end fraction(ii)
    Dividing Equation (i) by Equation (ii), we get
    fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals fraction numerator F subscript 1 end subscript. A subscript 2 end subscript. l subscript 1 end subscript. increment l subscript 2 end subscript over denominator F subscript 2 end subscript. A subscript 1 end subscript. l subscript 2 end subscript. increment l subscript 1 end subscript end fraction(iii)
    Force on steel wire from free body diagram
    T equals F subscript 1 end subscript equals left parenthesis 2 g right parenthesis Newton
    Force on brass wire from free body diagram
    F subscript 2 end subscript equals T subscript 1 end subscript superscript ´ ´ end superscript equals T plus 2 g equals 4 g Newton
    Now, putting the value of F subscript 1 end subscript comma F subscript 2 end subscript comma in Equation (iii), we get
    fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals open parentheses fraction numerator 2 g over denominator 4 g end fraction close parentheses. open parentheses fraction numerator pi r subscript 2 end subscript superscript 2 end superscript over denominator pi r subscript 1 end subscript superscript 2 end superscript end fraction close parentheses. open square brackets fraction numerator l subscript 1 end subscript over denominator l subscript 2 end subscript end fraction close square brackets. open parentheses fraction numerator increment l subscript 2 end subscript over denominator increment l subscript 1 end subscript end fraction close parentheses equals fraction numerator 1 over denominator 2 end fraction open parentheses fraction numerator 1 over denominator b subscript 2 end subscript end fraction close parentheses. a open parentheses fraction numerator increment l subscript 2 end subscript over denominator increment l subscript 1 end subscript end fraction close parentheses
    General
    chemistry-

    Salicin (structure given below) is a glycoside, found in the bark of willow tree, used in relieving pain. Observe the following reaction of salicin

    The correct statement (s) is (are) :

    Salicin (structure given below) is a glycoside, found in the bark of willow tree, used in relieving pain. Observe the following reaction of salicin

    The correct statement (s) is (are) :

    chemistry-General
    General
    chemistry-

    Magnetic moment of Cr (Z = 24), Mn+ (Z = 25) and Fe2+ (Z = 26) are a,b,c. They are in the order:

    Magnetic moment of Cr (Z = 24), Mn+ (Z = 25) and Fe2+ (Z = 26) are a,b,c. They are in the order:

    chemistry-General
    General
    physics-

    Which one of the following is the Young’s modules (in N divided by m to the power of 2 end exponent right parenthesis for the wire having the stress-strain curve shown in the figure

    Young’s modulus is defined only in elastic region and
    Y equals fraction numerator S t r e s s over denominator S t r a i n end fraction equals fraction numerator 8 cross times 10 to the power of 7 end exponent over denominator 4 cross times 10 to the power of negative 4 end exponent end fraction equals 2 cross times 10 to the power of 11 end exponent N divided by m to the power of 2 end exponent

    Which one of the following is the Young’s modules (in N divided by m to the power of 2 end exponent right parenthesis for the wire having the stress-strain curve shown in the figure

    physics-General
    Young’s modulus is defined only in elastic region and
    Y equals fraction numerator S t r e s s over denominator S t r a i n end fraction equals fraction numerator 8 cross times 10 to the power of 7 end exponent over denominator 4 cross times 10 to the power of negative 4 end exponent end fraction equals 2 cross times 10 to the power of 11 end exponent N divided by m to the power of 2 end exponent
    General
    physics-

    The diagram shows the change x in the length of a thin uniform wire caused by the application of stress F at two different temperatures T subscript 1 end subscriptand T subscript 2 end subscript. The variation shown suggest that

    Elasticity of wire decreases at high temperature i. e. at higher temperature slope of graph will be less
    So we can say that T subscript 1 end subscript greater than T subscript 2 end subscript

    The diagram shows the change x in the length of a thin uniform wire caused by the application of stress F at two different temperatures T subscript 1 end subscriptand T subscript 2 end subscript. The variation shown suggest that

    physics-General
    Elasticity of wire decreases at high temperature i. e. at higher temperature slope of graph will be less
    So we can say that T subscript 1 end subscript greater than T subscript 2 end subscript
    General
    chemistry-

    IHf ofICl(g),Cl(g),andI(g)is17.57,121.34and 106.96Jmol1respectively.Thenbonddissociation energyofIClbondis-

    IHf ofICl(g),Cl(g),andI(g)is17.57,121.34and 106.96Jmol1respectively.Thenbonddissociation energyofIClbondis-

    chemistry-General
    General
    chemistry-

    Calculateenthalpychangeofthefollowingreaction H2C=CH2(g)+H2(g)→H3CCH3(g) ThebondenergiesofC–H,C–C,C=C,H–Hare414, 347,615and435KJmol1respectively-

    Calculateenthalpychangeofthefollowingreaction H2C=CH2(g)+H2(g)→H3CCH3(g) ThebondenergiesofC–H,C–C,C=C,H–Hare414, 347,615and435KJmol1respectively-

    chemistry-General
    General
    chemistry-

    HeatevolvedinthereactionH2+Cl2 →2HClis 182KJ.BondenergiesofHH anCl–Clare430 and242KJ/morespectively.ThHCbond energy is-

    HeatevolvedinthereactionH2+Cl2 →2HClis 182KJ.BondenergiesofHH anCl–Clare430 and242KJ/morespectively.ThHCbond energy is-

    chemistry-General
    General
    chemistry-

    Among thfollowinfowhich reactioheat of reactiorepresents bond energof HCl

    Among thfollowinfowhich reactioheat of reactiorepresents bond energof HCl

    chemistry-General
    General
    chemistry-

    The correct statement(s) about the following sugars X and Y is(are) :

    The correct statement(s) about the following sugars X and Y is(are) :

    chemistry-General
    General
    chemistry-

    The following carbohydrate is

    The following carbohydrate is

    chemistry-General
    General
    chemistry-

    The correct functional group X and the reagent/reaction conditions Y in the following scheme are

    The correct functional group X and the reagent/reaction conditions Y in the following scheme are

    chemistry-General
    General
    chemistry-

    Observe the following laboratory tests for a–D(+) glucose and mention +ve or –ve ion from the code given below

    Observe the following laboratory tests for a–D(+) glucose and mention +ve or –ve ion from the code given below

    chemistry-General