Physics-
General
Easy

Question

Which of the following is equal to open parentheses 1 minus sin to the power of 2 end exponent invisible function application theta close parentheses sec to the power of 2 end exponent invisible function application theta

  1. 1    
  2. –1    
  3. 0    
  4. fraction numerator 1 over denominator 2 end fraction    

The correct answer is: 1

Related Questions to study

General
physics-

Which of the following is equal to cosec2

Which of the following is equal to cosec2

physics-General
General
physics-

Value of sin20° + cos2

Value of sin20° + cos2

physics-General
General
physics-

Value of tan invisible function application theta equals fraction numerator 2 over denominator square root of 5 end fraction comma find the value of sin20O +cos20O

Value of tan invisible function application theta equals fraction numerator 2 over denominator square root of 5 end fraction comma find the value of sin20O +cos20O

physics-General
parallel
General
physics-

The density of a material is 8 g/cc. In a unit system in which the unit length is 5 cm and unit mass is 20g, what is the density of the material?

The density of a material is 8 g/cc. In a unit system in which the unit length is 5 cm and unit mass is 20g, what is the density of the material?

physics-General
General
physics-

The density of a material is 8 g/cc. In a unit system in which the unit length is 5 cm and unit mass is 20g, what is the density of the material?

The density of a material is 8 g/cc. In a unit system in which the unit length is 5 cm and unit mass is 20g, what is the density of the material?

physics-General
General
maths-

In the given figure, if P Q perpendicular P S comma P Q parallel to S R comma angle S Q R equals 28 to the power of ring operator end exponent text end textand text end text angle Q R T equals 65 to the power of ring operator end exponent comma then the values of x and y respectively are

In the given figure, if P Q perpendicular P S comma P Q parallel to S R comma angle S Q R equals 28 to the power of ring operator end exponent text end textand text end text angle Q R T equals 65 to the power of ring operator end exponent comma then the values of x and y respectively are

maths-General
parallel
General
maths-

In the given figure, if lines PQ and RS intersect at point T, such that angle P R T equals 40 to the power of ring operator end exponent comma angle R P T equals 95 to the power of ring operator end exponent text end textand text end text angle T S Q equals 75 to the power of ring operator end exponent comma text  then  end text angle S Q T

In the given figure, if lines PQ and RS intersect at point T, such that angle P R T equals 40 to the power of ring operator end exponent comma angle R P T equals 95 to the power of ring operator end exponent text end textand text end text angle T S Q equals 75 to the power of ring operator end exponent comma text  then  end text angle S Q T

maths-General
General
maths-

In the given figure, if A B parallel to D E comma angle B A C equals 35 to the power of ring operator end exponent text end textand text end text angle C D E equals 53 to the power of ring operator end exponent, then DCE is

In the given figure, if A B parallel to D E comma angle B A C equals 35 to the power of ring operator end exponent text end textand text end text angle C D E equals 53 to the power of ring operator end exponent, then DCE is

maths-General
General
maths-

In the given capital delta X Y Z comma angle X equals 62 to the power of 0 end exponent comma angle X Y Z equals 54 to the power of ring operator end exponent If YO and ZO are the bisectors of ÐXYZ and ÐXZY respectively, then ÐOZY and ÐYOZ are

In the given capital delta X Y Z comma angle X equals 62 to the power of 0 end exponent comma angle X Y Z equals 54 to the power of ring operator end exponent If YO and ZO are the bisectors of ÐXYZ and ÐXZY respectively, then ÐOZY and ÐYOZ are

maths-General
parallel
General
maths-

In the given figure, sides QP and RQ of capital delta P Q Rare produced to points S and T respectively If angle S P R equals 135 to the power of ring operator end exponent text  and  end text angle P Q T equals 110 to the power of ring operator end exponent then angle text  PRQ end text is

In the given figure, sides QP and RQ of capital delta P Q Rare produced to points S and T respectively If angle S P R equals 135 to the power of ring operator end exponent text  and  end text angle P Q T equals 110 to the power of ring operator end exponent then angle text  PRQ end text is

maths-General
General
maths-

In the given figure, an equilateral triangle EDC surmounts the square ABCD then the value of x is

In the given figure, an equilateral triangle EDC surmounts the square ABCD then the value of x is

maths-General
General
maths-

In the given figure, AD BC perpendicular and AE is the bisector of angleBAC Then angleDAE is

In the given figure, AD BC perpendicular and AE is the bisector of angleBAC Then angleDAE is

maths-General
parallel
General
maths-

In the given figure, XY is parallel to PQ, then the measures of the angles x0 and y0 are

In the given figure, XY is parallel to PQ, then the measures of the angles x0 and y0 are

maths-General
General
maths-

In the given figure the sides AB and AC of a triangle are produced The bisectors of exterior angles B and C so formed intersect each other at point O angleBOC is

In the given figure the sides AB and AC of a triangle are produced The bisectors of exterior angles B and C so formed intersect each other at point O angleBOC is

maths-General
General
maths-

In the given figure, the bisectors of angleQ and angleR meet at the point O then angleQOR is

In the given figure, the bisectors of angleQ and angleR meet at the point O then angleQOR is

maths-General
parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.