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Maths-

General

Easy

Question

Prove that △ CAB ≅△ CAD

hint Hint:

Find the angles and sides that are equal and hence check the congruence.

The correct answer is: △CAB⩭△CAD by SAS congruence rule.

Complete step by step solution:
Consider 2 triangles, $straight triangle C A B$ and $straight triangle C A D$
From the figure, we have
AB = AD (given
$straight angle C A B equals straight angle C A D$ ( the included angle)
Also, AC = AC (common side)
∴ $straight triangle C A B approximately equal to straight triangle C A L$ by SAS congruence rule.

Related Questions to study

$AD comma BE comma CF text are the altitudes of a triangle end text ABC text . Prove that end text BD squared plus EC squared plus AF squared equals DC squared plus EA squared plus FB squared$

$AD comma BE comma CF text are the altitudes of a triangle end text ABC text . Prove that end text BD squared plus EC squared plus AF squared equals DC squared plus EA squared plus FB squared$

Write the following in expanded fractional form :
d) 0.00016

Write the following in expanded fractional form :
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In the kite shown, what additional information is required to
prove that △ CAB ≅△ CAD ?

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prove that △ CAB ≅△ CAD ?

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Write the following in expanded fractional form :
c) 4.00524

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parallel

Write the following in expanded fractional form :
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$A B C D text is a rectangle. end text D E text is perpendicular from end text D text to end text A C text . Prove that end text A D squared equals A E. A C$

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In the given picture, if AB = FE, BC = ED, $AB perpendicular BD$ and $FE perpendicular EC$ , then prove that AD = FC.

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In the given picture, $straight triangle ABC$ is an isosceles triangle with $AB equals AC$ and AD bisects the exterior angle A. Prove that
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In the given figure $AB equals AC equals AD comma space of 1em straight angle straight B equals 23 to the power of ring operator$ , and $straight angle D equals 47 to the power of ring operator$ . find $straight angle B C D$

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$text Prove that in a end text straight triangle A B C text , if end text A D text is perpendicular to end text B C text , then end text A B squared plus C D squared equals A C squared plus B D squared text . end text$

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parallel

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