Science

#### A thin homogeneous rod of mass m and length is free to rotate in vertical plane about a horizontal axle pivoted at one end of the rod. A small ball of mass m and charge q is attached to the opposite end of this rod. The whole system is positioned in a constant horizontal electric field of magnitude The rod is released from shown position from rest.

What is the acceleration of the small ball at the instant of releasing the rod?

ScienceIngestion-and-Digestion-1

#### Answer:The correct answer is:

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science

#### A thin homogeneous rod of mass m and length is free to rotate in vertical plane about a horizontal axle pivoted at one end of the rod. A small ball of mass m and charge q is attached to the opposite end of this rod. The whole system is positioned in a constant horizontal electric field of magnitude The rod is released from shown position from rest.

What is the angular acceleration of the rod at the instant of releasing the rod?

#### A thin homogeneous rod of mass m and length is free to rotate in vertical plane about a horizontal axle pivoted at one end of the rod. A small ball of mass m and charge q is attached to the opposite end of this rod. The whole system is positioned in a constant horizontal electric field of magnitude The rod is released from shown position from rest.

What is the angular acceleration of the rod at the instant of releasing the rod?

scienceingestion-and-digestion-1

science

#### Consider a finite charged rod. Electric field at Point P (shown) makes an angle with horizontal dotted line then angle is :-

Required angle

#### Consider a finite charged rod. Electric field at Point P (shown) makes an angle with horizontal dotted line then angle is :-

scienceingestion-and-digestion-1Required angle

scienceingestion-and-digestion-1

Required angle

science

#### The diagram shows a uniformly charged hemisphere of radius R. It has volume charge density . If the electric field at a point 2R distance above its centre is E then what is the electric field at the point which is 2R below its centre?

Apply principle of superposition

Electric field due to a uniformly charged sphere =

Apply principle of superposition

Electric field due to a uniformly charged sphere =

#### The diagram shows a uniformly charged hemisphere of radius R. It has volume charge density . If the electric field at a point 2R distance above its centre is E then what is the electric field at the point which is 2R below its centre?

scienceingestion-and-digestion-1

Apply principle of superposition

Electric field due to a uniformly charged sphere =

scienceingestion-and-digestion-1

Apply principle of superposition

Electric field due to a uniformly charged sphere =

science

#### A metallic rod of length l rotates at angular velocity about an axis passing through one end and perpendiuclar to the rod. If mass of electron is m and its charge is –e then the magnitude of potential difference between its two ends is

When rod rotates the centripetal acceleration of electron comes from electric field

Thus,

Thus,

#### A metallic rod of length l rotates at angular velocity about an axis passing through one end and perpendiuclar to the rod. If mass of electron is m and its charge is –e then the magnitude of potential difference between its two ends is

scienceingestion-and-digestion-1

When rod rotates the centripetal acceleration of electron comes from electric field

Thus,

Thus,

science

#### Uniform electric field of magnitude 100 V/m in space is directed along the line . Find the potential difference between point A (3, 1) & B (1,3).

Slope of line which is perpendicular to direction of electric field

#### Uniform electric field of magnitude 100 V/m in space is directed along the line . Find the potential difference between point A (3, 1) & B (1,3).

scienceingestion-and-digestion-1

Slope of line which is perpendicular to direction of electric field

science

#### A small electric dipole is placed at origin with its dipole moment directed along positive x-axis. The direction of electric field at point is

#### A small electric dipole is placed at origin with its dipole moment directed along positive x-axis. The direction of electric field at point is

scienceingestion-and-digestion-1

science

#### Four charges are placed at the circumference of a dial clock as shown in figure If the clock has only hour hand, then the resultant force on a charge placed at the centre, points in the direction which shows the time as :–

#### Four charges are placed at the circumference of a dial clock as shown in figure If the clock has only hour hand, then the resultant force on a charge placed at the centre, points in the direction which shows the time as :–

scienceingestion-and-digestion-1

scienceingestion-and-digestion-1

science

#### For a spherically symmetrical charge distribution, electric field at a distance r from the centre of sphere is where k is a constant. What will be the volume charge density at a distance r from the centre of sphere ?

By using Gauss law

(Note : Check dimensionally that r µ r6 )

(Note : Check dimensionally that r µ r6 )

#### For a spherically symmetrical charge distribution, electric field at a distance r from the centre of sphere is where k is a constant. What will be the volume charge density at a distance r from the centre of sphere ?

scienceingestion-and-digestion-1

By using Gauss law

(Note : Check dimensionally that r µ r6 )

(Note : Check dimensionally that r µ r6 )

science

#### Two positrons (e+) and two protons (P) are kept on four corners of a square of side a as shown in figure. The mass of proton is much larger than the mass of positron. Let q denotes the charge on the proton as well as the positron then the kinetic energies of one of the positrons and one of the protons respectively after a very long time will be

As mass of proton mass of positron so initial acceleration of positron is much larger than proton. Therefore positron reach far away in very short time as compare to proton

#### Two positrons (e+) and two protons (P) are kept on four corners of a square of side a as shown in figure. The mass of proton is much larger than the mass of positron. Let q denotes the charge on the proton as well as the positron then the kinetic energies of one of the positrons and one of the protons respectively after a very long time will be

scienceingestion-and-digestion-1As mass of proton mass of positron so initial acceleration of positron is much larger than proton. Therefore positron reach far away in very short time as compare to proton

scienceingestion-and-digestion-1

As mass of proton mass of positron so initial acceleration of positron is much larger than proton. Therefore positron reach far away in very short time as compare to proton