Maths-
General
Easy
Question
The Diagonals of a square ABCD meet at O. Prove that
Hint:
Hint :- using pythagoras theorem Find length of AC ,Find length of AO as the diagonals of square bisect each other.
The correct answer is: Hence proved
Aim :- Prove that
Let length of side of square be a
Then ,applying using pythagoras theorem in triangle ADC
We get
As diagonals bisect each other AC = 2OA
where a =AB
We get
Hence proved
Let length of side of square be a
Then ,applying using pythagoras theorem in triangle ADC
We get
As diagonals bisect each other AC = 2OA
where a =AB
We get
Hence proved
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