Maths-

General

Easy

Question

# In the figure, AD is a median to BC in and . and DE =

## The correct answer is: Hence proved

### Solution :-

Aim :- Prove that

Hint :- apply in pythagoras theorem on triangles AEB , AEC and AED Find and values .Now, add them and do necessary modification to get in terms of p and a.

Explanation(proof ) :-

As D is mid point BD = DC = BC/2 = a/2

Applying pythagoras theorem to triangle AEB we get ,

Applying pythagoras theorem to triangle AEC we get ,

Applying pythagoras theorem to triangle AED we get ,

Adding Eq 1 and Eq 2

We get

[By applying

Substitute Eq3 in the above condition

Hence proved

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