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Maths-

General

Easy

Question

The general solution of $fraction numerator tan space 5 x minus tan space 4 x over denominator 1 plus tan space 5 x tan space 4 x end fraction equals 1$ is

$n π + \frac{π}{4}; \forall n \in Z$
$n π \pm \frac{π}{4}, \forall n \in Z$
$ϕ$
$n π + \frac{π}{6}, \forall n \in Z$

The correct answer is: $n pi plus pi over 4 semicolon straight for all n element of Z$

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