Question

# The oxidation number of carboxylic carbon atom in is:

- +2
- +4
- +1
- +3

## The correct answer is: +3

### Related Questions to study

### The oxidation number of carboxylic carbon atom in is:

### The oxidation number of carboxylic carbon atom in is:

### The product (A) is:

### The product (A) is:

### If then is always

### If then is always

### The compound (A) is:

### The compound (A) is:

### The oxidation number of C in is:

### The oxidation number of C in is:

### has

In this question, we have to find the number of solution. In each quadrant tan value is different. Make two different case, one is where tan is positive ,[ 0 , π/2 ] U [π , 3 π/2 ] . And second case , tan is negative at [π/2 , π] U [3 π/2 , 2 π ] .

### has

In this question, we have to find the number of solution. In each quadrant tan value is different. Make two different case, one is where tan is positive ,[ 0 , π/2 ] U [π , 3 π/2 ] . And second case , tan is negative at [π/2 , π] U [3 π/2 , 2 π ] .

### If then for all real values of q

### If then for all real values of q

### The products (A) , (B) and (C) are:

### The products (A) , (B) and (C) are:

In the interval , the equation, has

In the interval , the equation, has

### oxidised product of , in the above reaction cannot be

### oxidised product of , in the above reaction cannot be

Let a, b, c, d R. Then the cubic equation of the type has either one root real or all three roots are real. But in case of trigonometric equations of the type can possess several solutions depending upon the domain of x. To solve an equation of the type a . The equation can be written as The solution is where =

On the domain [–, ] the equation possess

Let a, b, c, d R. Then the cubic equation of the type has either one root real or all three roots are real. But in case of trigonometric equations of the type can possess several solutions depending upon the domain of x. To solve an equation of the type a . The equation can be written as The solution is where =

On the domain [–, ] the equation possess