Maths-
General
Easy

Question

The value of p for which both the roots of the quadratic equation, 4 x squared minus 20 p x plus open parentheses 25 p squared plus 15 p minus 66 close parentheses are less than 2 lies in :

  1. left parenthesis 4 divided by 5 comma space 2 right parenthesis
  2. left parenthesis 2 comma space straight infinity right parenthesis
  3. left parenthesis negative 1 comma space 4 divided by 5 right parenthesis
  4. left parenthesis negative straight infinity comma negative 1 right parenthesis

hintHint:

Here we have given a quadratic equation, we have to find the value of p, where it lies. Find first D and relate inequality with p. Here roots are less than 2 and also find here inequality of p. Here f(2) > 0 so find p here and compare with those and look where it lies

The correct answer is: left parenthesis negative straight infinity comma negative 1 right parenthesis


    Here, we have to find the value of p and where it lies.
    Firstly, we have quadratic equation, 4 x squared minus 20 p x plus open parentheses 25 p squared plus 15 p minus 66 close parentheses.
    Also, the value of both roots is less than 2.
    4 x squared minus 20 p x plus open parentheses 25 p squared plus 15 p minus 66 close parentheses=0
    Now for discriminant,
    D greater or equal than 0 left square bracket D equals b squared – 4 a c right square bracket
    rightwards double arrow left parenthesis negative 20 p right parenthesis squared minus 4 cross times 4 left parenthesis 25 p squared plus 15 p minus 66 right parenthesis greater or equal than 0
    Solve this,
    rightwards double arrow 16 left square bracket 25 p squared minus 25 p squared minus 15 p plus 66 right square bracket greater or equal than 0
rightwards double arrow negative 15 p plus 66 greater or equal than 0
p less or equal than 66 over 15
p less or equal than 22 over 5 space space space................ open parentheses 1 close parentheses
    Now, we know that the root of the value is always less than 2 so we can write,
    rightwards double arrow fraction numerator negative b over denominator 2 a end fraction space less than space 2 space
fraction numerator 20 p over denominator 8 end fraction space less than space 2
rightwards double arrow p space less than fraction numerator space 16 over denominator 20 end fraction space
rightwards double arrow space p space less than 4 over 5 space minus left parenthesis 2 right parenthesis
    So, at x = 2 the quadratic equation is positive, we can write,
    f(2)>0
    rightwards double arrow 16 minus 40 p plus 25 p squared plus 15 p minus 66 greater than 0
rightwards double arrow 25 p squared minus 25 p minus 50 greater than 0
p squared minus p minus 2 greater than 0
    solving this by factorization, we have
    (p−2) (p+1) >0
    p > 2 and p < - 1
    Hence,
    p∈ (−∞, −1) ∪ (2, ∞) ---(3)
    From (1), (2) and (3), we get
    p belongs to (- −∞, −1)
    Therefore, the correct answer is (- −∞, −1)

    In this question, we have to find where the p lies. Here, we use discriminant, which is b squared – 4 a c. if D > 0 and D = 0 then real solution but if D < 0 then imaginary solution. Here we also us Factorization of quadratic equations.

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