Question

Which of the following are correct ?

- if and then n=m
^{4} - simplifies to an irrational number

^{4}

Hint:

### In this question, we have to find the which given option is correct. Here use the properties of logarithmic and solve each option and find which one is correct

## The correct answer is:

In this question, we have to find which option is correct. Check every option which one is satisfy. Use the properties of the logarithmic which going to help to get the answer.

### Related Questions to study

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Statement 2: is reduced to in acidic medium

### Statement 1:The reaction between and occurs in an acidic medium

Statement 2: is reduced to in acidic medium

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In this question, we have to find the number of cyphers. We need to remember that the cypher number can be found from the logarithmic calculation but to find the actual value or to visualize it we need to remove the logarithm. Here, log_{10}5 = 0.6990 and log_{10}3 = 0.4770.

Number of cyphers after decimal before a significant figure comes in is

In this question, we have to find the number of cyphers. We need to remember that the cypher number can be found from the logarithmic calculation but to find the actual value or to visualize it we need to remove the logarithm. Here, log_{10}5 = 0.6990 and log_{10}3 = 0.4770.

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In this question, we have to find where the p lies. Here, we use discriminant, which is . if D > 0 and D = 0 then real solution but if D < 0 then imaginary solution. Here we also us Factorization of quadratic equations.

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### If where determine b –

Just like we can change the base b for the exponential function, we can also change the base b for the logarithmic function. The logarithm with base b is defined so that

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### Statement 1:The two Fe atoms in have different oxidation numbers

Statement 2: ions decolourise solution

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Statement 2: ions decolourise solution

### , where and is

In this question, we have to find the . Here Solve first B. In B, rationalize it means multiply it denominator by sign change in both numerator and denominator

### , where and is

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Statement 1:The equivalence point refers the condition where equivalents of one species react with same number of equivalent of other species.

Statement 2:The end point of titration is exactly equal to equivalence point

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Statement 2:The end point of titration is exactly equal to equivalence point

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If and are the roots of the equation then the value of equals

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Statement 2:The iodine solution acts as an oxidant to reduce the reductant

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Statement 2:Grignard reagent acts as a reducing agent

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The first noble gas compound obtained was:

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Given that and then value of equals –

These four basic properties all follow directly from the fact that logs are exponents.

log_{b}(*xy*) = log_{b}*x* + log_{b}*y*.

log_{b}(*x/y*) = log_{b}*x* - log_{b}*y*.

log_{b}(*x ^{n}*) =

*n*log

_{b}

*x*.

log

_{b}

*x*= log

_{a}

*x*/ log

_{a}

*b*.

Given that and then value of equals –

These four basic properties all follow directly from the fact that logs are exponents.

log_{b}(*xy*) = log_{b}*x* + log_{b}*y*.

log_{b}(*x/y*) = log_{b}*x* - log_{b}*y*.

log_{b}(*x ^{n}*) =

*n*log

_{b}

*x*.

log

_{b}

*x*= log

_{a}

*x*/ log

_{a}

*b*.

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Statement 2:Change in colour is due to the complexation of alcohol with potassium dichromate.

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Total number of solutions of sin{x} = cos{x}, where {.} denotes the fractional part, in [0, 2] is equal to

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Statement 2:The colour change is due to the oxidation of potassium chromate.

Statement 1:If a strong acid is added to a solution of potassium chromate it changes itscolour from yellow to orange.

Statement 2:The colour change is due to the oxidation of potassium chromate.