Mathematics
Grade-7
Easy

Question

The value of 3 1 half space plus space open parentheses fraction numerator negative 2 over denominator 4 end fraction close parentheses is __________.

  1. 1
  2. 2
  3. 3
  4. 4

Hint:

Solve using BODMASS.

The correct answer is: 3


    STEP BY STEP SOLUTION
    3 1 half space minus space 2 over 4
C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l r space f r a c t i o n space
space equals space 7 over 2 space minus space 2 over 4 space
T a k i n g space L C M space o f space 2 & 4 space left parenthesis i. e space 4 right parenthesis
equals space fraction numerator 14 space minus space 2 over denominator 4 end fraction space equals space 12 over 4 space equals space 3

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