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Mathematics

Grade-7

Easy

Question

The value of $3 1 half space plus space open parentheses fraction numerator negative 2 over denominator 4 end fraction close parentheses$ is __________.

1
2
3
4

hint Hint:

Solve using BODMASS.

The correct answer is: 3

STEP BY STEP SOLUTION
$3 1 half space minus space 2 over 4 C o n v e r t i n g space m i x e d space f r a c t i o n space i n t o space s i m p l r space f r a c t i o n space space equals space 7 over 2 space minus space 2 over 4 space T a k i n g space L C M space o f space 2 & 4 space left parenthesis i. e space 4 right parenthesis equals space fraction numerator 14 space minus space 2 over denominator 4 end fraction space equals space 12 over 4 space equals space 3$

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