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Maths-

General

Easy

Question

A hemispherical bowl is made of steel of 0.25 cm thickness. The inner radius of the bowl is 5 cm. Find the volume of steel used.

hint Hint:

Volume of hemisphere is $2 over 3 pi r cubed$ .

The correct answer is: 41.265cm3

Explanation:

We have given a hemispherical bowl is made of steel of 0.25 cm thickness. The inner radius of the bowl is 5 cm.

We have to find the volume of the steel

We have given thickness of steel is 0.25cm
Inner radius is equal to 5cm
So, Outer radius is equal to 5 + 0.25 = 5.25cm
Outer Volume of the hemisphere will be
$V subscript o equals 2 over 3 pi r cubed$
$equals 2 over 3 pi left parenthesis 5.25 right parenthesis cubed$
$equals 303.065 cm cubed$
Inner volume will be
$V subscript i equals 2 over 3 pi r cubed$
$equals 2 over 3 pi left parenthesis 5 right parenthesis cubed$
$equals 261.799 cm cubed$
Therefore, the volume of steel used will be
$equals V subscript o minus V subscript i$
$equals 303.065 minus 261.799$
$equals 41.265 cm cubed$

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