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Question

A 12% brine solution was mixed with a 16% brine solution to produce a 15% brine solution. How much of the 12% brine solution and how much of the 16% brine solution were used to produce 40 L of the 15% solution?

hintHint:

let the 12 % brine solution be x L and the 16% brine solution mixed be y L
Total amount of mixed solution = amount of 12 % solution +amount of 16 % solution
= 40 L
Amount of salt in final brine solution = amount of salt in 15% brine solution
= amount of salt in 12% brine +  amount of salt in 16% brine

The correct answer is: 16%


    Ans :- 30 L of 12% brine solution and 10 L of 16% brine solution
    Explanation :-
    Step 1:-Frame system of linear equations by given condition
    Total amount of mixed solution = amount of 12 % solution +amount of 16 % solution
    x L plus y L equals 40 L not stretchy rightwards double arrow x plus y equals 40 — Eq1
    The amount of salt in 12% of x Litres brine solution = open parentheses 12 over 100 close parentheses straight x equals fraction numerator 3 x over denominator 25 end fraction
    The amount of salt in 16% of y Litres brine solution = open parentheses 10 over 100 close parentheses straight y equals fraction numerator 4 y over denominator 25 end fraction
    The amount of salt in 15% of  40 L of brine solution = open parentheses 15 over 100 close parentheses space cross times space 40 equals fraction numerator 15 space cross times space 10 over denominator 25 end fraction
    Amount of salt in final brine solution = amount of salt in 15% brine solution
    = amount of salt in 12% brine +  amount of salt in 16% brine
    We get, fraction numerator 3 x over denominator 25 end fraction plus fraction numerator 4 x over denominator 25 end fraction equals fraction numerator 15 ∗ 10 over denominator 25 end fraction not stretchy rightwards double arrow 3 x plus 4 y equals 150 — Eq2
    Step 2:- eliminate x to find the value of y .
    Doing (Eq2) -3(Eq1)  to eliminate x .
    left parenthesis 3 x plus 4 y right parenthesis minus 3 left parenthesis x plus y right parenthesis equals left parenthesis 150 right parenthesis minus 3 left parenthesis 40 right parenthesis
    3 x minus 3 x plus 4 y minus 3 y equals 150 minus 120
    y equals 30
    ∴y = 30
    Step 3:- find x by substituting the value of y in eq1.
    x plus y equals 40 not stretchy rightwards double arrow x plus 30 equals 40
    not stretchy rightwards double arrow x equals 40 minus 30 equals 10
    ∴x =10
    ∴30 L of 12% brine solution and 10 L of 16% brine solution is mixed to get 40 L of 15 % brine solution .

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