Maths-
General
Easy

Question

A hemispherical bowl is made of steel of 0.25 cm thickness. The inner radius of the bowl is 5 cm. Find the volume of steel used.

Hint:

Volume of hemisphere is 2 over 3 pi r cubed.

The correct answer is: 41.265cm3


    Explanation:
    • We have given a hemispherical bowl is made of steel of 0.25 cm thickness. The inner radius of the bowl is 5 cm.
    • We have to find the volume of the steel
    We have given thickness of steel is 0.25cm
    Inner radius is equal to 5cm
    So, Outer radius is equal to 5 + 0.25 = 5.25cm
    Outer Volume of the hemisphere will be

    V subscript o equals 2 over 3 pi r cubed

    equals 2 over 3 pi left parenthesis 5.25 right parenthesis cubed
    equals 303.065 cm cubed
    Inner volume will be

    V subscript i equals 2 over 3 pi r cubed

    equals 2 over 3 pi left parenthesis 5 right parenthesis cubed
    equals 261.799 cm cubed
    Therefore, the volume of steel used will be

    equals V subscript o minus V subscript i

    equals 303.065 minus 261.799
    equals 41.265 cm cubed

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