Maths-
General
Easy

Question

Babu left one-third of his property to his son, one-fourth to his daughter and the remainder to his wife. If his wife's share is Rs 1,80,000, what was the value of his property?

Hint:

let the Babus property be x ; find the Babu's son and  daughters property
Now find the remaining share of property which belongs to his wife  and equate it with Rs 1,80,000to get the total value of the property..

The correct answer is: Rs 4,32,000


    Ans :- Rs 4,32,000
    Explanation :-
    Step 1:- calculate the share of son and daughter
    Let the total value of Babu’s property be x
    Now, share of son = ⅓  of x  = x/3
    share of Daughter  = ¼ of x  = x/4
    Step 2:- Find share of wife
    Remaining value of property  = Total - son’s share - daughter’s share
    = x - (x/3) -(x/4)
    = (2x/3) - (x/4)
    = 5x/12
    The share of Babu’s wife is 5x/12
    Step 3:- equate the share of babu’s wife with Rs 1,80,000 to find total value of babu’s property
    5 x divided by 12 equals 1 comma 80 comma 000
    not stretchy rightwards double arrow 5 x equals 1 comma 80 comma 000 space cross times space 12
    not stretchy rightwards double arrow x equals 1.80 comma 000 space cross times space left parenthesis 12 divided by 5 right parenthesis equals 36 comma 000 space cross times space 12 equals 4 comma 32 comma 000
    ∴The total value of babu’s property = Rs 4,32,000

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