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General
Easy

Question

Given a rectangular room whose width is 4/7 of its length y and perimeter z. Write down an equation connecting y and z. Calculate the length of the rectangular room when the given perimeter is 4400 cm.

hintHint:

let the length of the rectangular room is y and width is 4/7 of length(i.e4y/7)
Perimeter of rectangular room z = 4400cm
Find perimeter in terms of lengths and width and solve to get the equation
Now substitute the value of z in the equation to get y.

The correct answer is: 1400 cm.


    Ans :- length of rectangle is 1400 cm .
    Explanation :-
    Step 1:- frame the equation from the given set of conditions .
    let the length of the rectangular room is y
    width is 4/7 of length  width = 4y/7
    Perimeter of rectangle = 2(length + width) = 2(y + fraction numerator 4 y over denominator 7 end fraction)
    Z = equals 2 open parentheses fraction numerator 11 y over denominator 7 end fraction close parentheses not stretchy rightwards double arrow 22 y equals 7 z
    The equation connecting y and z is 22y = 7z
    Step 2:- find the y by substituting z=4400cm(given)
    22 y equals 7 left parenthesis 4400 right parenthesis not stretchy rightwards double arrow y equals 7 left parenthesis 200 right parenthesis
    ∴ y = 1400 cm.
    ∴ length of the rectangle is 1400 cm .

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