Maths-
General
Easy

Question

The base of an isosceles triangle is 24 cm and its area is 192 cm2 . Find its perimeter

Hint:

Use the formula,
Area of an isosceles triangle = b over 2 square root of a squared minus b squared over 4 end root

The correct answer is: 64 cm


    It is given that base, b = 24 cm and
    Area of an isosceles triangle = 192 cm2
    b over 2 square root of a squared minus b squared over 4 end root equals 192 not stretchy rightwards double arrow 24 over 2 square root of a squared minus 24 squared over 4 end root equals 192
    12 square root of a squared minus 144 end root equals 192 not stretchy rightwards double arrow square root of a squared minus 144 end root equals 16
    a squared minus 144 equals 16 squared equals 256 not stretchy rightwards double arrow a squared equals 256 plus 144
    a squared equals 400 not stretchy rightwards double arrow a equals 20
    So, length of two equal sides = 20 cm
    Now, perimeter of the triangle = sum of all sides
    = 20 + 20 + 24 = 64 cm

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