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Physics-

General

Easy

Question

A train moves from one station to another 2 hours time. Its speed-time graph during this motion is shown in the figure. The maximum acceleration during the journey is

$140 k m h^{- 2}$
$160 k m h^{- 2}$
$100 k m h^{- 2}$
$120 k m h^{- 2}$

The correct answer is: $160 blank k m blank h to the power of negative 2 end exponent$

Maximum acceleration will be represented by $C D$ part of the graph
Acceleration $equals fraction numerator d v over denominator d t end fraction equals fraction numerator left parenthesis 60 minus 20 right parenthesis over denominator 0.25 end fraction equals 160 blank k m divided by h to the power of 2 end exponent$

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