Physics
Grade-10
Easy

Question

The force exerted on a current-carrying wire placed in a magnetic field is maximum when the angle between the wire and the direction of the magnetic field is

  1. 450
  2. 600
  3. 900
  4. 1800

hintHint:

Magnetic force acting on the charged particle   F=q(v×B)=qvB sinθ

The correct answer is: 900


    Magnetic force acting on the charged particle   F=q(v×B)=qvB sinθ
    If  θ=90 degree   sin90=1
     F=maximum
    Thus, magnetic force is maximum  If B and v   are perpendicular to each other hence angle = 90 degree 

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