Physics
Grade-10
Easy
Question
The force exerted on a current-carrying wire placed in a magnetic field is maximum when the angle between the wire and the direction of the magnetic field is
- 450
- 600
- 900
- 1800
Hint:
Magnetic force acting on the charged particle F=q(v×B)=qvB sinθ
The correct answer is: 900
Magnetic force acting on the charged particle F=q(v×B)=qvB sinθ
If θ=90 degree ⟹ sin90=1
⟹ F=maximum
Thus, magnetic force is maximum If B and v are perpendicular to each other hence angle = 90 degree
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