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Physics

Grade-10

Easy

Question

The force exerted on a current-carrying wire placed in a magnetic field is maximum when the angle between the wire and the direction of the magnetic field is

45⁰
60⁰
90⁰
180⁰

hint Hint:

Magnetic force acting on the charged particle $F = q (v \times B) = q v B sin θ$

The correct answer is: 90⁰

Magnetic force acting on the charged particle $F = q (v \times B) = q v B sin θ$
If $θ =9 0 degree$ $⟹ sin90 =1$
$⟹ F =maximum$
Thus, magnetic force is maximum If B and v are perpendicular to each other hence angle = 90 degree

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