Maths-
General
Easy

Question

A Rectangular piece of cardboard with dimensions 6 inches by 8 inches is used to make the curved side of a cylinder-shaped container. Using this cardboard What is the greatest volume of the cylinder can hold?

hintHint:

We fold the cardboard in two ways- first, we fold it by its length where its width will act as the height of the cylinder or, we fold it by its width where its length will act as the height of the cylinder. Lastly we compare these two volumes of cylinders to get the result.

The correct answer is: Using this cardboard, the greatest volume of the cylinder can hold is 96/π inch3.


    Explanations:
    Step 1 of 3:
    We fold it by the length.
    We have,  2 pi r subscript 1 equals 8 space of 1em not stretchy rightwards double arrow r subscript 1 equals fraction numerator 8 over denominator 2 pi end fraction , which is the base radius
    Height, h subscript 1  6 inch
    Volume = V subscript 1 equals pi open parentheses fraction numerator 8 over denominator 2 pi end fraction close parentheses squared cross times 6 equals 96 over pi inch cubed 

    Step 2 of 3:
    We fold it by the width.
    We have,2 pi r subscript 2 equals 6 space of 1em not stretchy rightwards double arrow r subscript 2 equals fraction numerator 6 over denominator 2 pi end fraction , which is the base radius
    Height,h subscript 1 equals 8 space inch
    Volume = V subscript 2 equals pi open parentheses fraction numerator 6 over denominator 2 pi end fraction close parentheses squared cross times 8 equals 72 over pi text  inch  end text cubed
    Step 3 of 3:

    It is clear that  V subscript 1 equals 96 over pi greater than 72 over pi equals V subscript 2 inch3, where volume of the cylinder ispi r squared h.
    Final Answer:
    Using this cardboard, the greatest volume of the cylinder can hold is 96/pi inch3.

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