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Chemistry-

General

Easy

Question

An organic compound reacts with $P C l subscript 5$ to give. The compound with sodium metal gives $n minus b u tan e. space T h u s comma space A space a n d space B space a r e colon$

$C_{2} H_{5} O H a n d C_{2} H_{5} C l$
$C_{2} H_{5} C l a n d C_{2} H_{5} O N a$
$C_{3} H_{7} O H a n d C H_{3} C H_{2} C H_{2} O C l$
$C_{4} H_{9} O H a n d C_{4} H_{9} O C l$

The correct answer is: $C subscript 2 H subscript 5 O H space a n d space C subscript 2 H subscript 5 C l$

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If f : R → R is continuous and differentiable function such that $not stretchy integral subscript negative 1 end subscript superscript x end superscript blank$ f(t) dt + f¢¢¢ (3) $not stretchy integral subscript x end subscript superscript 0 end superscript d t equals not stretchy integral subscript 1 end subscript superscript x end superscript blank$ t³
dt – f ¢ (1) $not stretchy integral subscript 0 end subscript superscript x end superscript blank$ t² dt + f ¢¢ (2) $not stretchy integral subscript x end subscript superscript 3 end superscript blank$ t. dt, then the value of f ¢ (4) is :

If f : R → R is continuous and differentiable function such that $not stretchy integral subscript negative 1 end subscript superscript x end superscript blank$ f(t) dt + f¢¢¢ (3) $not stretchy integral subscript x end subscript superscript 0 end superscript d t equals not stretchy integral subscript 1 end subscript superscript x end superscript blank$ t³
dt – f ¢ (1) $not stretchy integral subscript 0 end subscript superscript x end superscript blank$ t² dt + f ¢¢ (2) $not stretchy integral subscript x end subscript superscript 3 end superscript blank$ t. dt, then the value of f ¢ (4) is :

Assertion : The refractive index of diamond is $square root of 6$ and that of liquid is $square root of 3$
If the light travels from diamond to the liquid, it will totally reflected when the angle of incidence is 30^o
Reason : $mu equals fraction numerator 1 over denominator sin invisible function application C end fraction$ where $mu$ is the refractive index of diamond with respect to liquid

Assertion : The refractive index of diamond is $square root of 6$ and that of liquid is $square root of 3$
If the light travels from diamond to the liquid, it will totally reflected when the angle of incidence is 30^o
Reason : $mu equals fraction numerator 1 over denominator sin invisible function application C end fraction$ where $mu$ is the refractive index of diamond with respect to liquid

physics-General

If f : [0, p] → R is continuous and $not stretchy integral subscript 0 end subscript superscript pi end superscript blank$ f(x) sin x dx = $not stretchy integral subscript 0 end subscript superscript pi end superscript blank$ f(x) cos x dx = 0, then the number of roots of f(x) in (0, p) is

If f : [0, p] → R is continuous and $not stretchy integral subscript 0 end subscript superscript pi end superscript blank$ f(x) sin x dx = $not stretchy integral subscript 0 end subscript superscript pi end superscript blank$ f(x) cos x dx = 0, then the number of roots of f(x) in (0, p) is

parallel

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Reason : Wavelength of light depends on refractive index of medium

Assertion : Different colours travel with different speed in vacuum
Reason : Wavelength of light depends on refractive index of medium

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The following substance can be used as a raw material for obtaining alcohol:

The following substance can be used as a raw material for obtaining alcohol:

chemistry-General

Etherates are

Etherates are

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$E t h y l space a l c o h o l space r e a c t s space w i t h space H C l space b u t space n o t space w i t h space H C N space b e c a u s e colon$

$E t h y l space a l c o h o l space r e a c t s space w i t h space H C l space b u t space n o t space w i t h space H C N space b e c a u s e colon$

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Lucas reagent produces cloudiness immediately with:

Lucas reagent produces cloudiness immediately with:

chemistry-General

The product is

The product is

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Alloys of which metal are light and strong and are used in the manufacture of aeroplane parts?

Alloys of which metal are light and strong and are used in the manufacture of aeroplane parts?

chemistry-General

The right order of the solubility of sulphates of alkaline earth metals in water is

The right order of the solubility of sulphates of alkaline earth metals in water is

chemistry-General

$A space g a s space r e a c t s space w i t h space C a O space a n d space n o t space w i t h space N a H C O subscript 3 space i s colon$

$A space g a s space r e a c t s space w i t h space C a O space a n d space n o t space w i t h space N a H C O subscript 3 space i s colon$

chemistry-General

parallel

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If point O is the centre of a circle circumscribed about a triangle ABC. Then $Error converting from MathML to accessible text.$

Which pair of the following chlorides do not impart colour to the flame?

Which pair of the following chlorides do not impart colour to the flame?

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If for $A X equals B comma$ $B equals open square brackets table row cell 9 end cell row cell 52 end cell row cell 0 end cell end table close square brackets$ and $A to the power of negative 1 end exponent equals open square brackets table row 3 cell negative fraction numerator 1 over denominator 2 end fraction end cell cell negative fraction numerator 1 over denominator 2 end fraction end cell row cell negative 4 end cell cell rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow fraction numerator 3 over denominator 4 end fraction end cell cell fraction numerator 5 over denominator 4 end fraction end cell row 2 cell negative fraction numerator 1 over denominator 4 end fraction end cell cell negative fraction numerator 3 over denominator 4 end fraction end cell end table close square brackets$ ,then X is equal to

If for $A X equals B comma$ $B equals open square brackets table row cell 9 end cell row cell 52 end cell row cell 0 end cell end table close square brackets$ and $A to the power of negative 1 end exponent equals open square brackets table row 3 cell negative fraction numerator 1 over denominator 2 end fraction end cell cell negative fraction numerator 1 over denominator 2 end fraction end cell row cell negative 4 end cell cell rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow rightwards arrow over short leftwards arrow fraction numerator 3 over denominator 4 end fraction end cell cell fraction numerator 5 over denominator 4 end fraction end cell row 2 cell negative fraction numerator 1 over denominator 4 end fraction end cell cell negative fraction numerator 3 over denominator 4 end fraction end cell end table close square brackets$ ,then X is equal to

parallel

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