Chemistry-
General
Easy
Question
(A) and(C) are different compound s and rotate the plane-polarised light in the same direction, andboth are dextrorotatory. Both (A) and(C) do not show diastereomers, whichof the following statements are correct?
The correct answer is:
Related Questions to study
chemistry-
Which of the following dienes and dienophiles could be used to synthesise the following compound (A) ?
Which of the following dienes and dienophiles could be used to synthesise the following compound (A) ?
chemistry-General
Maths-
16 sin 
16 sin
Maths-General
physics-
Five conductors are meeting at a point x as shown in the figure. What is the value of current in fifth conductor?
According to Kirchhoff’s first law
(5A)+(4A)+(-3A)+(-5A)+I=0
Or I=-1A
(5A)+(4A)+(-3A)+(-5A)+I=0
Or I=-1A
Five conductors are meeting at a point x as shown in the figure. What is the value of current in fifth conductor?
physics-General
According to Kirchhoff’s first law
(5A)+(4A)+(-3A)+(-5A)+I=0
Or I=-1A
(5A)+(4A)+(-3A)+(-5A)+I=0
Or I=-1A
physics-
The figure shows a network of currents. The magnitude of current is shown here. The current I will be
Regarding Kirchhoff’s junction rule, the circuit can be redrawn as
Current in arm,
Current in arm,
Current in arm,
Hence,
Current in arm,
Current in arm,
Current in arm,
Hence,
The figure shows a network of currents. The magnitude of current is shown here. The current I will be
physics-General
Regarding Kirchhoff’s junction rule, the circuit can be redrawn as
Current in arm,
Current in arm,
Current in arm,
Hence,
Current in arm,
Current in arm,
Current in arm,
Hence,
physics-
The equivalent resistance between the terminals 
in the following circuit is
10
in series with 10 will gives(10+10)=20
and 10
in series with 10 will gives(10+10)=20
20
in parallel with 20 will gives
Resistance in series between points A and D
=5+10+5
=20
The equivalent resistance between the terminals in the following circuit is
physics-General
10
in series with 10 will gives(10+10)=20
and 10
in series with 10 will gives(10+10)=20
20
in parallel with 20 will givesResistance in series between points A and D
=5+10+5
=20
physics-
The equivalent resistance between points A and B of an infinite network of resistances, each of 1
, connected as shown is
Let 
be the equivalent resistance of entire network between A and B. Hence, we have
resistance of parallel combination of 1 and 
be the equivalent resistance of entire network between A and B. Hence, we have resistance of parallel combination of 1 and The equivalent resistance between points A and B of an infinite network of resistances, each of 1, connected as shown is
physics-General
Let be the equivalent resistance of entire network between A and B. Hence, we have
resistance of parallel combination of 1 and
be the equivalent resistance of entire network between A and B. Hence, we have resistance of parallel combination of 1 and 
Maths-
The period of 
is
Period of sin
As we know, if the period of f(x) is T then the period of g(f(x)) is also T.
So, period of sin(sin
) =2
As we know, if the period of f(x) is T then the period of g(f(x)) is also T.
So, period of sin(sin
) =2The period of is
Maths-General
Period of sin
As we know, if the period of f(x) is T then the period of g(f(x)) is also T.
So, period of sin(sin) =2
As we know, if the period of f(x) is T then the period of g(f(x)) is also T.
So, period of sin(sin
) =2Maths-
The period of 
is
f(x)=
Period of sin kx =
In numerator,
period of sin (
)=
In denominator,
period of sin (
)=
So, the period of f(x) is 1.
Period of sin kx =
In numerator,
period of sin (
)=In denominator,
period of sin (
)=So, the period of f(x) is 1.
The period of is
Maths-General
f(x)=
Period of sin kx =
In numerator,
period of sin ()=
In denominator,
period of sin ()=
So, the period of f(x) is 1.
Period of sin kx =
In numerator,
period of sin (
)=In denominator,
period of sin (
)=So, the period of f(x) is 1.
Maths-
Period of tan 4x+sec 4x is
f(x)= tan 4x + sec 4x
Period of tan 4x =
Period of sec 4x=
So, period of f(x)=LCM of
Period of tan 4x =
Period of sec 4x=
So, period of f(x)=LCM of
Period of tan 4x+sec 4x is
Maths-General
f(x)= tan 4x + sec 4x
Period of tan 4x =
Period of sec 4x=
So, period of f(x)=LCM of
Period of tan 4x =
Period of sec 4x=
So, period of f(x)=LCM of
Maths-
The cotangent function whose period 
is
Period of cot (k x) = 
given,
So, cotangent function whose period is
.
given,
So, cotangent function whose period is
.The cotangent function whose period is
Maths-General
Period of cot (k x) =
given,
So, cotangent function whose period is.
given,
So, cotangent function whose period is
.physics-
Thirteen resistances each of resistance R are connected in the circuit as shown in the figure. The effective resistance between points A and B is
Resistance R bisecting the circuit can be neglected due to the symmetry of the circuit.
Now, there are four triangles
Effective resistance of each triangle
Now the given circuit reduced to
Therefore, effective resistance between A and B,
Now, there are four triangles
Effective resistance of each triangle
Now the given circuit reduced to
Therefore, effective resistance between A and B,
Thirteen resistances each of resistance R are connected in the circuit as shown in the figure. The effective resistance between points A and B is
physics-General
Resistance R bisecting the circuit can be neglected due to the symmetry of the circuit.
Now, there are four triangles
Effective resistance of each triangle
Now the given circuit reduced to
Therefore, effective resistance between A and B,
Now, there are four triangles
Effective resistance of each triangle
Now the given circuit reduced to
Therefore, effective resistance between A and B,
physics-
Six resistors, each of value 3 are connected as shown in the figure. A cell of emf 3V is connected across 
The effective resistance across 
and the current through the arm will be
The equivalent circuit is shown as
We can emit the resistance in the arm DF as balance condition is satisfied.
Therefore, the 3 resistances in arm CD and DE are in series.
Similarly, for arms CF and FE, R’’=6
are in parallel
R’’’=3
Now, R’’’ and 3 resistances are in parallel
Moreover, V across AB=3V and resistance in the arm=3
∴ Current through the arm will be
We can emit the resistance in the arm DF as balance condition is satisfied.
Therefore, the 3
resistances in arm CD and DE are in series.Similarly, for arms CF and FE, R’’=6
are in parallelR’’’=3
Now, R’’’ and 3
resistances are in parallelMoreover, V across AB=3V and resistance in the arm=3
∴ Current through the arm will be
Six resistors, each of value 3 are connected as shown in the figure. A cell of emf 3V is connected across The effective resistance across and the current through the arm will be
physics-General
The equivalent circuit is shown as
We can emit the resistance in the arm DF as balance condition is satisfied.
Therefore, the 3 resistances in arm CD and DE are in series.
Similarly, for arms CF and FE, R’’=6
are in parallel
R’’’=3
Now, R’’’ and 3 resistances are in parallel
Moreover, V across AB=3V and resistance in the arm=3
∴ Current through the arm will be
We can emit the resistance in the arm DF as balance condition is satisfied.
Therefore, the 3
resistances in arm CD and DE are in series.Similarly, for arms CF and FE, R’’=6
are in parallelR’’’=3
Now, R’’’ and 3
resistances are in parallelMoreover, V across AB=3V and resistance in the arm=3
∴ Current through the arm will be
physics-
In the circuit shown the value of I in ampere is
We can simplify the network as shown
So, net resistance,
R=2.4+1.6=4.0
Therefore, current from the battery.
Now, from the circuit (b),
4I’ =6I
But
=I+I’
So, net resistance,
R=2.4+1.6=4.0
Therefore, current from the battery.
Now, from the circuit (b),
4I’ =6I
But
=I+I’In the circuit shown the value of I in ampere is
physics-General
We can simplify the network as shown
So, net resistance,
R=2.4+1.6=4.0
Therefore, current from the battery.
Now, from the circuit (b),
4I’ =6I
But=I+I’
So, net resistance,
R=2.4+1.6=4.0
Therefore, current from the battery.
Now, from the circuit (b),
4I’ =6I
But
=I+I’physics-
The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement?
The 
equation from the given graph can be written as,
Substituting
from Eq. (i), we get
Thus,
graph is a straight line with positive slope and negative intercept.
equation from the given graph can be written as,Substituting
from Eq. (i), we getThus,
graph is a straight line with positive slope and negative intercept.The given graph shows the variation of velocity with displacement. Which one of the graph given below correctly represents the variation of acceleration with displacement?
physics-General
The equation from the given graph can be written as,
Substituting from Eq. (i), we get
Thus, graph is a straight line with positive slope and negative intercept.
equation from the given graph can be written as,Substituting
from Eq. (i), we getThus,
graph is a straight line with positive slope and negative intercept.physics-
The displacement-time graphs of two moving particles make angles of 
with the 
axis. The ratio of their velocities is
Slope of displacement time-graph is velocity
The displacement-time graphs of two moving particles make angles of with the axis. The ratio of their velocities is
physics-General
Slope of displacement time-graph is velocity
