Chemistry-
General
Easy

Question

Cl2(g)→2Cl(g),In this procesvaluof ΔH wilbe-

  1. Positive    
  2. Negative    
  3. Zero    
  4. Nothingcanbepredicted    

The correct answer is: Positive

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Related Questions to study

General
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The enthalpy change for there action 2C(graphite)+3H2(g)→C2H6(g)icalled–

The enthalpy change for there action 2C(graphite)+3H2(g)→C2H6(g)icalled–

chemistry-General
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This reaction is called

This reaction is called

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General
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Which of the following is a nonreducing sugar?

Which of the following is a nonreducing sugar?

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Which of the following aldohexoses give the same osazone derivative ?

Which of the following aldohexoses give the same osazone derivative ?

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Observe the following laboratory tests for a–D(+) glucose and mention +ve or –ve ion from the code given below

Observe the following laboratory tests for a–D(+) glucose and mention +ve or –ve ion from the code given below

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General
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The correct functional group X and the reagent/reaction conditions Y in the following scheme are

The correct functional group X and the reagent/reaction conditions Y in the following scheme are

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General
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The following carbohydrate is

The following carbohydrate is

chemistry-General
General
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The correct statement(s) about the following sugars X and Y is(are) :

The correct statement(s) about the following sugars X and Y is(are) :

chemistry-General
General
physics-

A copper rod of length L and radius ris suspended from the ceiling by one of its ends. What will be elongation of the rod due to its own weight when rho blank a n d blank Y are the density and Young’s modulus of the copper respectively?

The weight of the rod can be assumed to act at its mid-point.
Now, the mass of the rod is
M equals V rho
M equals A L rho
Here, A equals a r e a blank o f blank c r o s s minus s e c t i o n s comma
L= length of the rod.
Now, we know that the Young’s modulus

Y equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A bullet l blank end fraction blank left parenthesis H e r e comma blank L equals fraction numerator L over denominator 2 end fraction comma l equals e x t e n s i o n right parenthesis
l equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A Y end fraction
or l equals fraction numerator M g L over denominator 2 A Y end fraction
On putting the value of M from Eq.(i), we get
l equals fraction numerator A L rho bullet g L over denominator 2 A Y end fraction
orl equals fraction numerator rho g L to the power of 2 end exponent over denominator 2 Y end fraction

A copper rod of length L and radius ris suspended from the ceiling by one of its ends. What will be elongation of the rod due to its own weight when rho blank a n d blank Y are the density and Young’s modulus of the copper respectively?

physics-General
The weight of the rod can be assumed to act at its mid-point.
Now, the mass of the rod is
M equals V rho
M equals A L rho
Here, A equals a r e a blank o f blank c r o s s minus s e c t i o n s comma
L= length of the rod.
Now, we know that the Young’s modulus

Y equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A bullet l blank end fraction blank left parenthesis H e r e comma blank L equals fraction numerator L over denominator 2 end fraction comma l equals e x t e n s i o n right parenthesis
l equals fraction numerator fraction numerator M g L over denominator 2 end fraction over denominator A Y end fraction
or l equals fraction numerator M g L over denominator 2 A Y end fraction
On putting the value of M from Eq.(i), we get
l equals fraction numerator A L rho bullet g L over denominator 2 A Y end fraction
orl equals fraction numerator rho g L to the power of 2 end exponent over denominator 2 Y end fraction
General
physics-

The value of force constant between the applied elastic force F and displacement will be

Force constant, K equals tan invisible function application 30 degree equals 1 divided by square root of 3

The value of force constant between the applied elastic force F and displacement will be

physics-General
Force constant, K equals tan invisible function application 30 degree equals 1 divided by square root of 3
General
physics-

A student plots a graph from his reading on the determination of Young’s modulus of a metal wire but forgets to label. The quantities on X and Y axes may be respectively

A student plots a graph from his reading on the determination of Young’s modulus of a metal wire but forgets to label. The quantities on X and Y axes may be respectively

physics-General
General
physics-

If the ratio of lengths, radii and Young’s modulus of steel and brass wires shown in the figure are a comma blank band c, respectively. The ratio between the increase in lengths of brass and steel wires would be

Given, fraction numerator l subscript 1 end subscript over denominator l subscript 2 end subscript end fraction equals a comma fraction numerator r subscript 1 end subscript over denominator r subscript 2 end subscript end fraction equals b comma fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals c

Let Young’s modulus of steel be Y subscript 1 end subscript, and that of brass be Y subscript 2 end subscript
therefore Y subscript 1 end subscript equals fraction numerator F subscript 1 end subscript l subscript 1 end subscript over denominator A subscript 1 end subscript increment l subscript 1 end subscript end fraction (i)
and Y subscript 2 end subscript equals fraction numerator F subscript 2 end subscript l subscript 2 end subscript over denominator A subscript 2 end subscript increment l subscript 2 end subscript end fraction(ii)
Dividing Equation (i) by Equation (ii), we get
fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals fraction numerator F subscript 1 end subscript. A subscript 2 end subscript. l subscript 1 end subscript. increment l subscript 2 end subscript over denominator F subscript 2 end subscript. A subscript 1 end subscript. l subscript 2 end subscript. increment l subscript 1 end subscript end fraction(iii)
Force on steel wire from free body diagram
T equals F subscript 1 end subscript equals left parenthesis 2 g right parenthesis Newton
Force on brass wire from free body diagram
F subscript 2 end subscript equals T subscript 1 end subscript superscript ´ ´ end superscript equals T plus 2 g equals 4 g Newton
Now, putting the value of F subscript 1 end subscript comma F subscript 2 end subscript comma in Equation (iii), we get
fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals open parentheses fraction numerator 2 g over denominator 4 g end fraction close parentheses. open parentheses fraction numerator pi r subscript 2 end subscript superscript 2 end superscript over denominator pi r subscript 1 end subscript superscript 2 end superscript end fraction close parentheses. open square brackets fraction numerator l subscript 1 end subscript over denominator l subscript 2 end subscript end fraction close square brackets. open parentheses fraction numerator increment l subscript 2 end subscript over denominator increment l subscript 1 end subscript end fraction close parentheses equals fraction numerator 1 over denominator 2 end fraction open parentheses fraction numerator 1 over denominator b subscript 2 end subscript end fraction close parentheses. a open parentheses fraction numerator increment l subscript 2 end subscript over denominator increment l subscript 1 end subscript end fraction close parentheses

If the ratio of lengths, radii and Young’s modulus of steel and brass wires shown in the figure are a comma blank band c, respectively. The ratio between the increase in lengths of brass and steel wires would be

physics-General
Given, fraction numerator l subscript 1 end subscript over denominator l subscript 2 end subscript end fraction equals a comma fraction numerator r subscript 1 end subscript over denominator r subscript 2 end subscript end fraction equals b comma fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals c

Let Young’s modulus of steel be Y subscript 1 end subscript, and that of brass be Y subscript 2 end subscript
therefore Y subscript 1 end subscript equals fraction numerator F subscript 1 end subscript l subscript 1 end subscript over denominator A subscript 1 end subscript increment l subscript 1 end subscript end fraction (i)
and Y subscript 2 end subscript equals fraction numerator F subscript 2 end subscript l subscript 2 end subscript over denominator A subscript 2 end subscript increment l subscript 2 end subscript end fraction(ii)
Dividing Equation (i) by Equation (ii), we get
fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals fraction numerator F subscript 1 end subscript. A subscript 2 end subscript. l subscript 1 end subscript. increment l subscript 2 end subscript over denominator F subscript 2 end subscript. A subscript 1 end subscript. l subscript 2 end subscript. increment l subscript 1 end subscript end fraction(iii)
Force on steel wire from free body diagram
T equals F subscript 1 end subscript equals left parenthesis 2 g right parenthesis Newton
Force on brass wire from free body diagram
F subscript 2 end subscript equals T subscript 1 end subscript superscript ´ ´ end superscript equals T plus 2 g equals 4 g Newton
Now, putting the value of F subscript 1 end subscript comma F subscript 2 end subscript comma in Equation (iii), we get
fraction numerator Y subscript 1 end subscript over denominator Y subscript 2 end subscript end fraction equals open parentheses fraction numerator 2 g over denominator 4 g end fraction close parentheses. open parentheses fraction numerator pi r subscript 2 end subscript superscript 2 end superscript over denominator pi r subscript 1 end subscript superscript 2 end superscript end fraction close parentheses. open square brackets fraction numerator l subscript 1 end subscript over denominator l subscript 2 end subscript end fraction close square brackets. open parentheses fraction numerator increment l subscript 2 end subscript over denominator increment l subscript 1 end subscript end fraction close parentheses equals fraction numerator 1 over denominator 2 end fraction open parentheses fraction numerator 1 over denominator b subscript 2 end subscript end fraction close parentheses. a open parentheses fraction numerator increment l subscript 2 end subscript over denominator increment l subscript 1 end subscript end fraction close parentheses
General
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Salicin (structure given below) is a glycoside, found in the bark of willow tree, used in relieving pain. Observe the following reaction of salicin

The correct statement (s) is (are) :

Salicin (structure given below) is a glycoside, found in the bark of willow tree, used in relieving pain. Observe the following reaction of salicin

The correct statement (s) is (are) :

chemistry-General
General
physics-

Which one of the following is the Young’s modules (in N divided by m to the power of 2 end exponent right parenthesis for the wire having the stress-strain curve shown in the figure

Young’s modulus is defined only in elastic region and
Y equals fraction numerator S t r e s s over denominator S t r a i n end fraction equals fraction numerator 8 cross times 10 to the power of 7 end exponent over denominator 4 cross times 10 to the power of negative 4 end exponent end fraction equals 2 cross times 10 to the power of 11 end exponent N divided by m to the power of 2 end exponent

Which one of the following is the Young’s modules (in N divided by m to the power of 2 end exponent right parenthesis for the wire having the stress-strain curve shown in the figure

physics-General
Young’s modulus is defined only in elastic region and
Y equals fraction numerator S t r e s s over denominator S t r a i n end fraction equals fraction numerator 8 cross times 10 to the power of 7 end exponent over denominator 4 cross times 10 to the power of negative 4 end exponent end fraction equals 2 cross times 10 to the power of 11 end exponent N divided by m to the power of 2 end exponent
General
physics-

The diagram shows the change x in the length of a thin uniform wire caused by the application of stress F at two different temperatures T subscript 1 end subscriptand T subscript 2 end subscript. The variation shown suggest that

Elasticity of wire decreases at high temperature i. e. at higher temperature slope of graph will be less
So we can say that T subscript 1 end subscript greater than T subscript 2 end subscript

The diagram shows the change x in the length of a thin uniform wire caused by the application of stress F at two different temperatures T subscript 1 end subscriptand T subscript 2 end subscript. The variation shown suggest that

physics-General
Elasticity of wire decreases at high temperature i. e. at higher temperature slope of graph will be less
So we can say that T subscript 1 end subscript greater than T subscript 2 end subscript