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    Maths-
    General
    Easy

    Question

    Convert 15 % into fraction :

    1. 4 over 30
    2. 2 over 10
    3. 3 over 20
    4. 1 over 12

    The correct answer is: 3 over 20

      15% = 15 over 100
      Divide numerator and denominator by 5:
      fraction numerator begin display style bevelled 15 over 5 end style over denominator begin display style bevelled 100 over 5 end style end fraction = 3 over 20

      Related Questions to study

      General
      Maths-

      What is the LCM of 8 and 15 :

      1. 120
      2. 60
      3. 130
      4. 140

      What is the LCM of 8 and 15 :

      Maths-General
      1. 120
      2. 60
      3. 130
      4. 140
      General
      Maths-

      Find angle x and y :

      1. x= 80 , y = 100
      2. x = 60, y =70
      3. x=80, y=80
      4. x=20 , y=100

      Find angle x and y :

      Maths-General
      1. x= 80 , y = 100
      2. x = 60, y =70
      3. x=80, y=80
      4. x=20 , y=100
      General
      Maths-

      What is the LC M of 9 and 18:

      1. 1
      2. 9
      3. 18
      4. 6

      What is the LC M of 9 and 18:

      Maths-General
      1. 1
      2. 9
      3. 18
      4. 6
      parallel
      General
      Maths-

      Find the GCF of 9 and 16 :

      1. 1
      2. 0
      3. 9
      4. 16

      Find the GCF of 9 and 16 :

      Maths-General
      1. 1
      2. 0
      3. 9
      4. 16
      General
      Chemistry-

      The correct statement about the following disaccharide is:
      I)
      II)

      1. ring (II) is pyranose with beta minusglycosidic link    
      2. ring (I) is furanose with alpha -glycosidic link    
      3. ring (I) is pyranose with alpha-glycosidic link    
      4. ring (II) is furanose with alpha -glycosidic link    

      The correct statement about the following disaccharide is:
      I)
      II)

      Chemistry-General
      1. ring (II) is pyranose with beta minusglycosidic link    
      2. ring (I) is furanose with alpha -glycosidic link    
      3. ring (I) is pyranose with alpha-glycosidic link    
      4. ring (II) is furanose with alpha -glycosidic link    
      General
      Chemistry-

      A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S.
      table row cell P fraction numerator 1. M e M g B r over denominator 2. H to the power of plus end exponent comma H subscript 2 end subscript O end fraction Q fraction numerator 1. O subscript 3 end subscript over denominator 2. Z n comma H subscript 2 end subscript O end fraction R fraction numerator 1. O H to the power of minus end exponent over denominator 2. capital delta end fraction S end cell row cell 3. H subscript 2 end subscript S O subscript 4 end subscript comma capital delta end cell end table
      The structures of the products Q and R, respectively, are:

      1.    
      2.    
      3.    
      4.    

      A carbonyl compound P, which gives positive iodoform test, undergoes reaction with MeMgBr followed by dehydration to give an olefin Q. Ozonolysis of Q leads to a dicarbonyl compound R, which undergoes intramolecular aldol reaction to give predominantly S.
      table row cell P fraction numerator 1. M e M g B r over denominator 2. H to the power of plus end exponent comma H subscript 2 end subscript O end fraction Q fraction numerator 1. O subscript 3 end subscript over denominator 2. Z n comma H subscript 2 end subscript O end fraction R fraction numerator 1. O H to the power of minus end exponent over denominator 2. capital delta end fraction S end cell row cell 3. H subscript 2 end subscript S O subscript 4 end subscript comma capital delta end cell end table
      The structures of the products Q and R, respectively, are:

      Chemistry-General
      1.    
      2.    
      3.    
      4.    
      parallel
      General
      Chemistry-

      Consider the following reactions I and II,
      I)
      II)
      Products 'X' and 'Y' are respectively:

      1. styphnic acid, picric acid    
      2. picric acid, benzoic acid    
      3. picric acid, styphnic acid    
      4. picric acid, salicylic acid    

      Consider the following reactions I and II,
      I)
      II)
      Products 'X' and 'Y' are respectively:

      Chemistry-General
      1. styphnic acid, picric acid    
      2. picric acid, benzoic acid    
      3. picric acid, styphnic acid    
      4. picric acid, salicylic acid    
      General
      Chemistry-

      In which of the following cases, the nitration will take place at meta-position?
      I)
      II)
      III)
      IV)

      1. II and IV    
      2. I,II and III    
      3. I only    
      4. II and III    

      In which of the following cases, the nitration will take place at meta-position?
      I)
      II)
      III)
      IV)

      Chemistry-General
      1. II and IV    
      2. I,II and III    
      3. I only    
      4. II and III    
      General
      Chemistry-

      The correct order of decreasing basicity of the following compounds is:
      I)
      II)
      III)
      IV)

      1. I>II>III>IV    
      2. II>I>III>IV    
      3. III>IV>I>II    
      4. II>I.IV>III    

      The correct order of decreasing basicity of the following compounds is:
      I)
      II)
      III)
      IV)

      Chemistry-General
      1. I>II>III>IV    
      2. II>I>III>IV    
      3. III>IV>I>II    
      4. II>I.IV>III    
      parallel
      General
      Chemistry-

      Phenol . gives two polymers on condensation with formaldehyde:

      X and Y are :

      1. n o v o l a k blank n o v o l a k    
      2. b a k e l i t e blank b a k e l i t e    
      3. n o v o l a k blank b a k e l i t e    
      4. b a k e l i t e blank n o v o l a k    

      Phenol . gives two polymers on condensation with formaldehyde:

      X and Y are :

      Chemistry-General
      1. n o v o l a k blank n o v o l a k    
      2. b a k e l i t e blank b a k e l i t e    
      3. n o v o l a k blank b a k e l i t e    
      4. b a k e l i t e blank n o v o l a k    
      General
      Chemistry-

      X and Yare:

      1. g u t t a blank p e r c h a blank n a t u r a l blank r u b b e r    
      2. g u t t a blank p e r c h a blank g u t t a blank p e r c h a    
      3. n a t u r a l blank r u b b e r blank g u t t a blank p e r c h a    
      4. n a t u r a l blank r u b b e r blank n a t u r a l blank r u b b e r    

      X and Yare:

      Chemistry-General
      1. g u t t a blank p e r c h a blank n a t u r a l blank r u b b e r    
      2. g u t t a blank p e r c h a blank g u t t a blank p e r c h a    
      3. n a t u r a l blank r u b b e r blank g u t t a blank p e r c h a    
      4. n a t u r a l blank r u b b e r blank n a t u r a l blank r u b b e r    
      General
      Chemistry-

      1. copolymer    
      2. addition polymer    
      3. thermosetting polymer    
      4. homopolymer    

      Chemistry-General
      1. copolymer    
      2. addition polymer    
      3. thermosetting polymer    
      4. homopolymer    
      parallel
      General
      Maths-

      Simplify : 2m-3 =17

      1. 9
      2. 5
      3. 10
      4. 7

      Simplify : 2m-3 =17

      Maths-General
      1. 9
      2. 5
      3. 10
      4. 7
      General
      Physics-

      In the figure is shown Young’s double slit experiment. Q is the position of the first bright fringe on the right side of O. P is the 11th fringe on the other side, as measured from Q. If the wavelength of the light used is 6000 cross times 1 0 to the power of negative 10 end exponent m, then S subscript 1 end subscript B will be equal to

      1. 3.138 cross times 1 0 to the power of negative 7 end exponent m    
      2. 6.6 cross times 1 0 to the power of negative 6 end exponent m    
      3. 3.144 cross times 1 0 to the power of negative 7 end exponent m    
      4. 6 cross times 1 0 to the power of negative 6 end exponent m    

      In the figure is shown Young’s double slit experiment. Q is the position of the first bright fringe on the right side of O. P is the 11th fringe on the other side, as measured from Q. If the wavelength of the light used is 6000 cross times 1 0 to the power of negative 10 end exponent m, then S subscript 1 end subscript B will be equal to

      Physics-General
      1. 3.138 cross times 1 0 to the power of negative 7 end exponent m    
      2. 6.6 cross times 1 0 to the power of negative 6 end exponent m    
      3. 3.144 cross times 1 0 to the power of negative 7 end exponent m    
      4. 6 cross times 1 0 to the power of negative 6 end exponent m    
      General
      Physics-

      When one of the slits of Young’s experiment is covered with a transparent sheet of thickness 4.8 mm, the central fringe shifts to a position originally occupied by the 30th bright fringe. What should be the thickness of the sheet if the central fringe has to shift to the position occupied by 20th bright fringe

      1. 3.8 mm 
      2. 3.2 mm 
      3. 1.6 mm 
      4. 7.6 mm 

      When one of the slits of Young’s experiment is covered with a transparent sheet of thickness 4.8 mm, the central fringe shifts to a position originally occupied by the 30th bright fringe. What should be the thickness of the sheet if the central fringe has to shift to the position occupied by 20th bright fringe

      Physics-General
      1. 3.8 mm 
      2. 3.2 mm 
      3. 1.6 mm 
      4. 7.6 mm 
      parallel

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