If m and n are order and degree of the equatio ((d^(2)y)/(dx^(2-Turito

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Question

If m and n are order and degree of the equation $open parentheses fraction numerator d squared y over denominator d x squared end fraction close parentheses to the power of 5 plus 4 times fraction numerator open parentheses fraction numerator d squared y over denominator d x squared end fraction close parentheses cubed over denominator fraction numerator d cubed y over denominator d x cubed end fraction end fraction plus fraction numerator d cubed y over denominator d x cubed end fraction equals x squared minus 1$ then

m = 3, n = 3
m = 3, n = 2
m = 3, n = 5
m = 3, n = 1

Hint:

In this question we have to find the order and degree of the given differential equation. For this we will first arrange the equation in a proper way. Now we know that the order of a differential equation is the order of the highest order derivative involved in the differential equation and the degree of a differential equation is the exponent of the highest order derivative involved in the differential equation.

The correct answer is: m = 3, n = 2

$open parentheses fraction numerator d squared y over denominator d x squared end fraction close parentheses to the power of 5 plus 4 times fraction numerator open parentheses fraction numerator d squared y over denominator d x squared end fraction close parentheses cubed over denominator fraction numerator d cubed y over denominator d x cubed end fraction end fraction plus open parentheses fraction numerator d cubed y over denominator d x cubed end fraction close parentheses equals x squared minus 1 rightwards double arrow open parentheses fraction numerator d squared y over denominator d x squared end fraction close parentheses to the power of 5 fraction numerator d cubed y over denominator d x cubed end fraction plus 4 open parentheses fraction numerator d squared y over denominator d x squared end fraction close parentheses cubed plus open parentheses fraction numerator d cubed y over denominator d x cubed end fraction close parentheses squared equals open parentheses x squared minus 1 close parentheses fraction numerator d cubed y over denominator d x cubed end fraction N 0 w space w e space c a n space s a y space t h a t space o r d e r comma m equals 3 space a n d space d e g r e e comma n equals 2 space$

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m = 3, n = 3
m = 3, n = 2
m = 3, n = 5
m = 3, n = 1

Hint:

Answer

The correct answer is: m = 3, n = 2

Solution

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If m and n are order and degree of the equation then

m = 3, n = 3m = 3, n = 2m = 3, n = 5m = 3, n = 1

Hint:

Answer

The correct answer is: m = 3, n = 2

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m = 3, n = 3
m = 3, n = 2
m = 3, n = 5
m = 3, n = 1