If sum_(n=3)^(oo)(^(n)e_(3))/(n!)=a*e^(b)+c then descending-Turito

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Maths-

General

Easy

Question

If $sum from n equals 3 to straight infinity of fraction numerator blank to the power of n C subscript 3 over denominator n factorial end fraction equals a times e to the power of b plus c$ then descending order of $a comma b comma c$
is

$a, b, c$
$a, c, b$
$b, c, a$
$b, a, c$

The correct answer is: $b comma a comma c$

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