Maths-

General

Easy

Question

# If have a common factor then 'a' is equal to

- 24
- 1
- 2
- 12

Hint:

### In this question we will assume the common root to be and so both the equation will be equal using that root in both the equation, so, using this equation we will find the common root. Later putting that root in any one equation we can find the value of a.

## The correct answer is: 24

### Related Questions to study

physics-

A block C of mass is moving with velocity and collides elastically with block of mass and connected to another block of mass through spring constant .What is if is compression of spring when velocity of is same ?

Using conservation of linear momentum, we

have

Or

Using conservation of energy, we have

Where compression in the spring

Or

have

Or

Using conservation of energy, we have

Where compression in the spring

Or

A block C of mass is moving with velocity and collides elastically with block of mass and connected to another block of mass through spring constant .What is if is compression of spring when velocity of is same ?

physics-General

Using conservation of linear momentum, we

have

Or

Using conservation of energy, we have

Where compression in the spring

Or

have

Or

Using conservation of energy, we have

Where compression in the spring

Or

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### If then ascending order of A, B, C.

### If then ascending order of A, B, C.

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### The number of different seven digit numbers that can be written using only the three digits 1, 2 and 3 with the condition that the digit 2 occurs twice in each number is-

Complete step by step solution:

We are given the number of different seven-digit numbers that can be written using only three digits 1,2 and 3. Therefore,

Total number of Digits = 7

We are given that the digit two occurs exactly twice in each number.

Thus, the digit two occurs twice in the seven digit number.

Now, we will find the number of ways of arrangement of the digit two in the seven digit number by using combination.

Total number of ways that the digit two occurs exactly twice in each number =

Now, the remaining five digits can be written using two digits 1 and 3 in ways.

We will now find the total number of seven digit number by multiplying the number of ways of arrangement in both the cases. Therefore

Total number of seven digit number =

Now by using the formula

, we get

Total number of seven digit number =

We know that the factorial can be written by the formula n! = n(n-1)! , so we get

Total number of seven digit number =

Total number of seven digit number =

Simplifying the expression, we get

Total number of seven digit number =

Multiplying the terms, we get

Total number of seven digit number = 672

Therefore, the number of different seven-digit numbers that can be written using only three digits 1,2 and 3 is 672.

We are given the number of different seven-digit numbers that can be written using only three digits 1,2 and 3. Therefore,

Total number of Digits = 7

We are given that the digit two occurs exactly twice in each number.

Thus, the digit two occurs twice in the seven digit number.

Now, we will find the number of ways of arrangement of the digit two in the seven digit number by using combination.

Total number of ways that the digit two occurs exactly twice in each number =

Now, the remaining five digits can be written using two digits 1 and 3 in ways.

We will now find the total number of seven digit number by multiplying the number of ways of arrangement in both the cases. Therefore

Total number of seven digit number =

Now by using the formula

, we get

Total number of seven digit number =

We know that the factorial can be written by the formula n! = n(n-1)! , so we get

Total number of seven digit number =

Total number of seven digit number =

Simplifying the expression, we get

Total number of seven digit number =

Multiplying the terms, we get

Total number of seven digit number = 672

Therefore, the number of different seven-digit numbers that can be written using only three digits 1,2 and 3 is 672.

### The number of different seven digit numbers that can be written using only the three digits 1, 2 and 3 with the condition that the digit 2 occurs twice in each number is-

Maths-General

Complete step by step solution:

We are given the number of different seven-digit numbers that can be written using only three digits 1,2 and 3. Therefore,

Total number of Digits = 7

We are given that the digit two occurs exactly twice in each number.

Thus, the digit two occurs twice in the seven digit number.

Now, we will find the number of ways of arrangement of the digit two in the seven digit number by using combination.

Total number of ways that the digit two occurs exactly twice in each number =

Now, the remaining five digits can be written using two digits 1 and 3 in ways.

We will now find the total number of seven digit number by multiplying the number of ways of arrangement in both the cases. Therefore

Total number of seven digit number =

Now by using the formula

, we get

Total number of seven digit number =

We know that the factorial can be written by the formula n! = n(n-1)! , so we get

Total number of seven digit number =

Total number of seven digit number =

Simplifying the expression, we get

Total number of seven digit number =

Multiplying the terms, we get

Total number of seven digit number = 672

Therefore, the number of different seven-digit numbers that can be written using only three digits 1,2 and 3 is 672.

We are given the number of different seven-digit numbers that can be written using only three digits 1,2 and 3. Therefore,

Total number of Digits = 7

We are given that the digit two occurs exactly twice in each number.

Thus, the digit two occurs twice in the seven digit number.

Now, we will find the number of ways of arrangement of the digit two in the seven digit number by using combination.

Total number of ways that the digit two occurs exactly twice in each number =

Now, the remaining five digits can be written using two digits 1 and 3 in ways.

We will now find the total number of seven digit number by multiplying the number of ways of arrangement in both the cases. Therefore

Total number of seven digit number =

Now by using the formula

, we get

Total number of seven digit number =

We know that the factorial can be written by the formula n! = n(n-1)! , so we get

Total number of seven digit number =

Total number of seven digit number =

Simplifying the expression, we get

Total number of seven digit number =

Multiplying the terms, we get

Total number of seven digit number = 672

Therefore, the number of different seven-digit numbers that can be written using only three digits 1,2 and 3 is 672.

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Statement-II : If then

Which of the above statements is true

Statement-I : If then A=

statement 1 is true.

Statement-II : If then

statement 2 is false.

statement 1 is true.

Statement-II : If then

statement 2 is false.

### Statement-I : If then A=

Statement-II : If then

Which of the above statements is true

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Statement-I : If then A=

statement 1 is true.

Statement-II : If then

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statement 1 is true.

Statement-II : If then

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