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The centre of the circle r squared minus 2 r left parenthesis 3 c o s space theta plus 4 s i n space theta right parenthesis minus 24 is

  1. open square brackets 5 comma t a n to the power of negative 1 end exponent invisible function application left parenthesis 4 divided by 3 right parenthesis close square brackets    
  2. open square brackets 13 comma t a n to the power of negative 1 end exponent invisible function application left parenthesis 5 divided by 12 right parenthesis close square brackets    
  3. open square brackets 15 comma t a n to the power of negative 1 end exponent invisible function application left parenthesis 5 divided by 3 right parenthesis close square brackets    
  4. open square brackets 9 comma t a n to the power of negative 1 end exponent invisible function application left parenthesis 6 divided by 5 right parenthesis close square brackets    

The correct answer is: open square brackets 5 comma t a n to the power of negative 1 end exponent invisible function application left parenthesis 4 divided by 3 right parenthesis close square brackets

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