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Maths-

General

Easy

Question

In $blank subscript straight triangle ABC$ $A equals pi over 4 text and end text tan text end text B tan space C equals P n$ $t h e n space a l l space p o s s i b l e space v a l u e s space o f space P space i s$

$(- \infty, 3 - 2 \sqrt{2}) \cup (3 + 2 \sqrt{2}, \infty)$
$(- \infty, 3 - 2 \sqrt{2}] \cup [3 + 2 \sqrt{2}, \infty)$
$(3 - 2 \sqrt{2}, 3 + 2 \sqrt{2})$
$[3 - 2 \sqrt{2}, 3 + 2 \sqrt{2}]$

The correct answer is: $left parenthesis negative straight infinity comma 3 minus 2 square root of 2 right square bracket union left square bracket 3 plus 2 square root of 2 comma straight infinity right parenthesis$

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