Maths-
General
Easy

Question

𝐴𝑃 is perpendicular bisector of 𝐵𝐶.
1. What segment lengths are equal? Explain your reasoning.
2. Find AB.
3. Explain why D is on 𝐴𝑃.

hintHint:

  • Perpendicular bisector theorem
  • According to perpendicular bisector theorem, in the triangle, any point on perpendicular bisector is at equal distance from both end points of the line segment on which it is drawn.

The correct answer is: 1. equal segments AB = BC, BD = DC and BP = PC 2. AB = 4 units. 3.Yes, D lie on AP.


    Answer:
    • Step by step explanation: 
      • Given:

    AB = 6x - 5.

    AC = 4x + 1.

    BD = 13

    DC = 13
    straight angle APB equals straight angle APC equals 90 to the power of ring operator
    AP is perpendicular bisector at BC.

    • Step 1:
    In straight triangle ABC comma
    AP is perpendicular bisector.
    Therefore, points on AP are equidistant from B and C
    So,

    AB = AC

    6x – 5 = 4x + 1

    6x – 4x = 5 + 1

    2x = 6

    X equals 3 over 2

    x = 1.5

    AB = 6x – 5

    AB = 6(1.5) – 5

    AB = 9 – 5

    AB = 4

    • Step 2:
    • Given:

    BD = 13

    DC = 13

    text  As  end text straight angle APB equals straight angle APC equals 90 to the power of ring operator

    Therefore, straight angle DPB equals straight angle DPC equals 90 to the power of ring operator

    Also, BP = PC
    DP is perpendicular bisector on BC from D.
    Also,
    As point D is equidistant from B and C
    Therefore, D lies on DP

    • Final Answer: 
    1. equal segments AB = BC, BD = DC and BP = PC
    2. AB = 4 units.
    3. Yes, D lie on AP.

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