Maths-
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Easy

Question

Assertion : Let f colon R minus left curly bracket 1 , 2 comma 3 right curly bracket rightwards arrow R be a function defined by f(x) = fraction numerator 1 over denominator x minus 1 end fraction plus fraction numerator 2 over denominator x minus 2 end fraction plus fraction numerator 3 over denominator x minus 3 end fraction. Then f is many-one function.
Reason : If either f apostrophe left parenthesis x right parenthesis greater than 0 or f to the power of apostrophe left parenthesis x right parenthesis less than 0 comma for all x element ofdomain of f, then y = f(x) is one-one function.</span

  1. If both (A) and (R) are true, and (R) is the correct explanation of (A) .    
  2. If both (A) and (R) are true but (R) is not the correct explanation of (A) .    
  3. If (A) is true but (R) is false.    
  4. If (A) is false but (R) is true.    

The correct answer is: If (A) is false but (R) is true.

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