Physics-
General
Easy
Question
A frictionless track
ends in a circular loop of radius
. A body slides down the track from point
which is it
height
. Maximum value of
for the body to successfully complete the loop is

The correct answer is: 
Condition for vertical looping

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Related Questions to study
physics-
Velocity-time graph of a particle of mass 2 kg moving in a straight line is as shown in figure. Work done by all forces on the particle is

Initial velocity of particle, 
Final velocity of the particle,
According to work-energy theorem,




Final velocity of the particle,
According to work-energy theorem,
Velocity-time graph of a particle of mass 2 kg moving in a straight line is as shown in figure. Work done by all forces on the particle is

physics-General
Initial velocity of particle, 
Final velocity of the particle,
According to work-energy theorem,




Final velocity of the particle,
According to work-energy theorem,
maths-
Domain of definition of the function
, is
Domain of definition of the function
, is
maths-General
physics-
If
represent the work done in moving a particle from A to B along three different paths 1, 2 and 3 respectively(as shown)in the gravitational field of a point mass m. Find the correct relation between 

Gravitational field is a conservative force field. In a conservative force field work done is path independent.

If
represent the work done in moving a particle from A to B along three different paths 1, 2 and 3 respectively(as shown)in the gravitational field of a point mass m. Find the correct relation between 

physics-General
Gravitational field is a conservative force field. In a conservative force field work done is path independent.

physics-
Given below is a graph between a variable force
(along
-axis) and the displacement
(along
-axis) of a particle in one dimension. The work done by the force in the displacement interval between
and
is

Given below is a graph between a variable force
(along
-axis) and the displacement
(along
-axis) of a particle in one dimension. The work done by the force in the displacement interval between
and
is

physics-General
physics-
A particle of mass
moving with a velocity
makes an elastic one dimensional collision with a stationary particle of mass
establishing a contact with it for extremely small time
. Their force of contact increases from zero to
linearly in time
, remains constant for a further time
and decreases linearly from
to zero in further time
as shown. The magnitude possessed by
is

Change in momentum = Impulse
= Area under force-time graph
Area of trapezium

= Area under force-time graph
A particle of mass
moving with a velocity
makes an elastic one dimensional collision with a stationary particle of mass
establishing a contact with it for extremely small time
. Their force of contact increases from zero to
linearly in time
, remains constant for a further time
and decreases linearly from
to zero in further time
as shown. The magnitude possessed by
is

physics-General
Change in momentum = Impulse
= Area under force-time graph
Area of trapezium

= Area under force-time graph
maths-
Let
be a set containing 10 distinct elements, then the total number of distinct functions from
to
is-
Let
be a set containing 10 distinct elements, then the total number of distinct functions from
to
is-
maths-General
maths-
The number of bijective functions from set A to itself when a contains 106 elements-
The number of bijective functions from set A to itself when a contains 106 elements-
maths-General
physics-
The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of
is

Work done
area under
graph
= area of trapezium
area of trapezium 


= area of trapezium
The work done by a force acting on a body is as shown in the graph. The total work done in covering an initial distance of
is

physics-General
Work done
area under
graph
= area of trapezium
area of trapezium 


= area of trapezium
physics-
A particle is acted upon by a force
which varies with position
as shown in figure. If the particle at
has kinetic energy of 25 J, then the kinetic energy of the particle at
is

Work done=area between the graph force displacement curve and displacement


According to work energy theorem


=20+25
=45J
According to work energy theorem
=20+25
=45J
A particle is acted upon by a force
which varies with position
as shown in figure. If the particle at
has kinetic energy of 25 J, then the kinetic energy of the particle at
is

physics-General
Work done=area between the graph force displacement curve and displacement


According to work energy theorem


=20+25
=45J
According to work energy theorem
=20+25
=45J
physics-
A vertical spring with force constant
is fixed on a table. A ball of mass
at a height
above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance
. The net work done in the process is

Gravitational potential energy of ball gets converted into elastic potential energy of the spring 
Net work done
Net work done
A vertical spring with force constant
is fixed on a table. A ball of mass
at a height
above the free upper end of the spring falls vertically on the spring so that the spring is compressed by a distance
. The net work done in the process is

physics-General
Gravitational potential energy of ball gets converted into elastic potential energy of the spring 
Net work done
Net work done
physics-
Figure shows the
-
graph. Where
is the force applied and
is the distance covered

By the body along a straight line path. Given that
is in
and
in
, what is the work done?
Work done =area under curve and displacement axis

Figure shows the
-
graph. Where
is the force applied and
is the distance covered

By the body along a straight line path. Given that
is in
and
in
, what is the work done?
physics-General
Work done =area under curve and displacement axis

maths-
Range of function f(x) =
,
is given by -
]
(C)
(C)
Range of function f(x) =
,
is given by -
maths-General
]
(C)
(C)
physics-
A light inextensible string that goes over a smooth fixed pulley as shown in the figure connects two blocks of masses
and
. Taking
, find the work done (in joules) by the string on the block of mass
during the first second after the system is released from rest

In the given condition tension in the string



And acceleration of each block

Let ‘S’ is the distance covered by block of mass
in first sec

Work done by the string 


And acceleration of each block
Let ‘S’ is the distance covered by block of mass
A light inextensible string that goes over a smooth fixed pulley as shown in the figure connects two blocks of masses
and
. Taking
, find the work done (in joules) by the string on the block of mass
during the first second after the system is released from rest

physics-General
In the given condition tension in the string



And acceleration of each block

Let ‘S’ is the distance covered by block of mass
in first sec

Work done by the string 


And acceleration of each block
Let ‘S’ is the distance covered by block of mass
physics-
An object of mass
is tied to a string of length
and a variable horizontal force is applied on it which starts at zero and gradually increases until the string makes an angel
with the vertical. Work done by the force
is

(Since, change in kinetic energy is zero)

Here,
An object of mass
is tied to a string of length
and a variable horizontal force is applied on it which starts at zero and gradually increases until the string makes an angel
with the vertical. Work done by the force
is

physics-General
(Since, change in kinetic energy is zero)

Here,
physics-
A block of mass
kg sliding on a smooth horizontal surface with a velocity
meets the spring of spring constant
fixed at one end as shown in figure. The maximum compression of the spring and velocity of block as is returns to the original position respectively are

When block strikes the spring, the kinetic energy of block converts into potential energy of spring ie,

Or

When block returns to the original position, again potential energy converts into kinetic energy of the blocks, so velocity of the block is same as before but its sign changes as it goes to mean position.

Or
When block returns to the original position, again potential energy converts into kinetic energy of the blocks, so velocity of the block is same as before but its sign changes as it goes to mean position.
A block of mass
kg sliding on a smooth horizontal surface with a velocity
meets the spring of spring constant
fixed at one end as shown in figure. The maximum compression of the spring and velocity of block as is returns to the original position respectively are

physics-General
When block strikes the spring, the kinetic energy of block converts into potential energy of spring ie,

Or

When block returns to the original position, again potential energy converts into kinetic energy of the blocks, so velocity of the block is same as before but its sign changes as it goes to mean position.

Or
When block returns to the original position, again potential energy converts into kinetic energy of the blocks, so velocity of the block is same as before but its sign changes as it goes to mean position.