### Question

#### There were two women participating in a chess tournament Every participant played two games with the other participants the number of games that the men played between themselves proved to exceed by 66 the number of games that the men played with the women The number of participants is

- 6
- 11
- 13
- 10

#### The correct answer is: 13

## Book A Free Demo

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### Related Questions to study

#### 153 games were played at a chess tournament with each contestant playing once against each of the others The number of participants is

#### 153 games were played at a chess tournament with each contestant playing once against each of the others The number of participants is

The number of different ways in which a committee of 4 members formed out of 6 Asians, 3 Europeans and 4 Americans if the committee is to have at least one from each of the 3 regional groups is

The number of different ways in which a committee of 4 members formed out of 6 Asians, 3 Europeans and 4 Americans if the committee is to have at least one from each of the 3 regional groups is

A committee of5 is to be formed from 6 boys and 5 girls The number of ways that the committee can be formed so that the committee contains at least one boy and one girl having majority of boys is

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#### If n and are integers such that then n c (n‐l, r‐l)=

#### If n and are integers such that then n c (n‐l, r‐l)=

#### The least value of the natural number n satisfying

#### The least value of the natural number n satisfying

#### then (n, r)=

#### then (n, r)=

#### then ‘n’ is

#### then ‘n’ is

#### If = mC_{2}, then C_{2} is equal to -

We will expand the expression by using the identity

Hence,

It is also known that

n! = n.(n-1). (n-2)…..

Then,

We have to find the value of which is also equal to

Also, we can rewrite it as

On substituting the values of , we will get,

Solve the brackets

Multiply and divide by

We can write m-3 as ((m+1) - 4)

Then,

Multiply and divide by 3 to make expression 4! in the denominator

#### If = mC_{2}, then C_{2} is equal to -

We will expand the expression by using the identity

Hence,

It is also known that

n! = n.(n-1). (n-2)…..

Then,

We have to find the value of which is also equal to

Also, we can rewrite it as

On substituting the values of , we will get,

Solve the brackets

Multiply and divide by

We can write m-3 as ((m+1) - 4)

Then,

Multiply and divide by 3 to make expression 4! in the denominator