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Easy

Question

Fifth term of G.P is 2 The product of its first nine terms is

  1. 1024    
  2. 256    
  3. 512    
  4. 356    

hintHint:

Given is only the fifth term of the G.P. and asked to find the product of 9 terms. We will consider the first term as a and the r be the common ratio of the whole G.P. then we can simply equate the fifth term as a r to the power of 4 space equals space 2 . Then remaining 9 terms will be multiplied such that their product will be in the form of
a space cross times space a r space cross times space a r squared space cross times space a r cubed space cross times space a r to the power of 4 space cross times........ space cross times a r to the power of 8  and we will try to adjust this in the form of fifth term. So let’s solve it!

The correct answer is: 512


     Detailed Solution
    Given that
    5 to the power of t h end exponent term of a G.P. is 2
    Let first term as a and the r be the common ratio of the whole G.P.

    Then fifth term will be a r to the power of 4 space equals space 2
    But we are asked to find the product of 9 terms of the G.P.

    So we can write the product as  a space cross times space a r space cross times space a r squared space cross times space a r cubed space cross times space a r to the power of 4 space cross times........ space cross times a r to the power of 8
    So ,

     rightwards double arrow a space cross times space a r space cross times space a r squared space cross times space a r cubed space cross times space a r to the power of 4 space cross times space a r to the power of 5 space cross times a r to the power of 6 space cross times a r to the power of 7 space space cross times a r to the power of 8
     
    Now we can write the terms with base a separately and those with r separately.
    rightwards double arrow a a a a a a a a a cross times r r squared r cubed space r to the power of 4 r to the power of 5 r to the power of 6 r to the power of 7 r to the power of 8
     
     
     
    Now adding the powers of the bases separately,
    rightwards double arrow a to the power of 1 plus 1 plus 1 plus 1 plus 1 plus 1 plus 1 plus 1 plus 1 end exponent cross times r to the power of 1 plus 2 plus 3 plus 4 plus 5 plus 6 plus 7 plus 8 end exponent space equals space a to the power of 9 r to the power of 36
     
     
    But we have to write this in the form of power 4,
    rightwards double arrow a to the power of 9 r to the power of 36 space equals space a to the power of 9 r to the power of 9 cross times 4 end exponent
     
    Now we will take the common power out,
    rightwards double arrow left parenthesis a r to the power of 4 right parenthesis to the power of 9
     
    Putting the value of fifth term in above bracket,
     
    rightwards double arrow left parenthesis 2 right parenthesis to the power of 9 space equals space 512
     
     
     
    Thus, the product of its first nine terms is 512.
     

    Here note that the fifth term is having fourth power of 2 and not fifth power. We need not to find all nine terms separately; only finding the product is enough because that product will then be written in the form of the term that is known. Terms in a G.P. are having a common ratio in between. That’s why the power of r is increasing as the terms are increasing.

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