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Question

If A = open square brackets table row 4 2 row cell negative 1 end cell 1 end table close square brackets, then (A –2I) (A –3I) = 

  1. A    
  2. I    
  3. 0    
  4. 5I    

The correct answer is: 0


    open parentheses open square brackets table attributes columnalign center center columnspacing 1em end attributes row 4 2 row cell negative 1 end cell 1 end table close square brackets minus 2 open square brackets table attributes columnalign left left columnspacing 1em end attributes row cell 1      0 end cell row cell 0      1 end cell end table close square brackets close parentheses open parentheses open square brackets table row 4 2 row cell negative 1 end cell 1 end table close square brackets minus 3 open square brackets table row 1 0 row 0 1 end table close square brackets close parentheses
    = open square brackets table attributes columnalign center center columnspacing 1em end attributes row 2 2 row cell negative 1 end cell cell negative 1 end cell end table close square brackets open square brackets table row 1 2 row cell negative 1 end cell cell negative 2 end cell end table close square brackets= open square brackets table row 0 0 row 0 0 end table close square brackets= 0

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