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Easy

Question

If A is a matrix of order 3 × 4, then both ABT and BTA are defined if order of B is -

  1. 3 × 3    
  2. 4 × 4    
  3. 4 × 3    
  4. 3 × 4    

hintHint:

 

The correct answer is: 3 × 4


    we are given that A is a matrix of order 3 × 4 and asked to find the order of matrix B
    Given A is a 3×4 matrix and B is a matrix such that A′B,B′A are both defined.
    We know that, we can multiply two matrices if, and only if, the number of columns in the first matrix equals the number of rows in the second matrix.
    Since A is a 3×4 matrix, A′ the transpose of A is a 4×3 matrix.We have A′B is defined.
    By the definition of multiplication of two matrices, we get the number of rows in matrix B as 3.        ....(1)
    Also we have B′A is defined.
    We have number of rows in matrix B is 3, then number of columns in matrix B′ is 3.
    Since A is a 3×4 matrix and B′A is defined.
    Therefore number of rows in matrix B′ is 4.
    ⇒ number of columns in matrix B is 4.   ....(2)
    Thus by (1) and (2), we get
    The order of matrix B as 3×4

    Therefore the order of matrix B is 3x4

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