If alpha,beta be that roots 4x^(2)-16 x+lambda=0 where-Turito

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If $alpha comma beta$ be that roots $4 x squared minus 16 x plus lambda equals 0$ where $lambda element of R$ , such that $1 less than alpha less than 2$ and $2 less than beta less than 3$ then the number of integral solutions of λ is

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5
3
2
6

Answer:The correct answer is: 3

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If α,β then the equation $x squared minus 3 x plus 1 equals 0$ with roots $fraction numerator 1 over denominator alpha minus 2 end fraction comma fraction numerator 1 over denominator beta minus 2 end fraction$ will be

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If b > a , then the equation, (x - a) (x - b) - 1 = 0, has:

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Statement-I : If $fraction numerator 3 x plus 4 over denominator left parenthesis x plus 1 right parenthesis squared left parenthesis x minus 1 right parenthesis end fraction equals fraction numerator A over denominator x minus 1 end fraction plus fraction numerator B over denominator x plus 1 end fraction plus fraction numerator C over denominator left parenthesis x plus 1 right parenthesis squared end fraction$ then A= $7 over 4$
Statement-II : If $fraction numerator p x plus q over denominator left parenthesis 2 x minus 3 right parenthesis squared end fraction equals fraction numerator 1 over denominator 2 x minus 3 end fraction plus fraction numerator 3 over denominator left parenthesis 2 x minus 3 right parenthesis squared end fraction$ then $p equals 2 comma q equals 3$
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The foot of the perpendicular from $left parenthesis negative 1 comma pi divided by 6 right parenthesis$ on the line $r left parenthesis 3 s i n space theta plus square root of 3 c o s space theta right parenthesis equals 3$ is

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For the circle $r equals 6 C o s space theta$ centre and radius are

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The polar equation of the circle of radius 5 and touching the initial line at the pole is

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The equation of the circle with centre at $open parentheses 1 comma 0 to the power of 0 end exponent close parentheses$ , which passes through the point $open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses$ is

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The centre of the circle $r squared minus 2 r left parenthesis 3 c o s space theta plus 4 s i n space theta right parenthesis minus 24$ is

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The circle with centre at and radius 2 is

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The centre and radius of the circle $r equals c o s space theta minus s i n space theta$ are respectively

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If be that roots where , such that and then the number of integral solutions of λ is

532 6

Answer:The correct answer is: 3

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If α,β then the equation with roots will be

If α,β then the equation with roots will be

If b > a , then the equation, (x - a) (x - b) - 1 = 0, has:

If b > a , then the equation, (x - a) (x - b) - 1 = 0, has:

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If $alpha comma beta$ be that roots $4 x squared minus 16 x plus lambda equals 0$ where $lambda element of R$ , such that $1 less than alpha less than 2$ and $2 less than beta less than 3$ then the number of integral solutions of λ is

5
3
2
6

If α,β then the equation $x squared minus 3 x plus 1 equals 0$ with roots $fraction numerator 1 over denominator alpha minus 2 end fraction comma fraction numerator 1 over denominator beta minus 2 end fraction$ will be

If α,β then the equation $x squared minus 3 x plus 1 equals 0$ with roots $fraction numerator 1 over denominator alpha minus 2 end fraction comma fraction numerator 1 over denominator beta minus 2 end fraction$ will be

The line passing through the points $open parentheses 2 comma fraction numerator pi over denominator 2 end fraction close parentheses$ , (3,0) is

The line passing through the points $open parentheses 2 comma fraction numerator pi over denominator 2 end fraction close parentheses$ , (3,0) is

The equation of the line parallel to $r left square bracket 3 C o s space theta plus 2 S i n space theta right square bracket equals 5$ and passing through $open parentheses 2 comma fraction numerator pi over denominator 2 end fraction close parentheses$ is

The equation of the line parallel to $r left square bracket 3 C o s space theta plus 2 S i n space theta right square bracket equals 5$ and passing through $open parentheses 2 comma fraction numerator pi over denominator 2 end fraction close parentheses$ is

The foot of the perpendicular from the pole on the line $r left parenthesis c o s space theta plus square root of 3 s i n space theta right parenthesis equals 2$ is

The foot of the perpendicular from the pole on the line $r left parenthesis c o s space theta plus square root of 3 s i n space theta right parenthesis equals 2$ is

The foot of the perpendicular from $left parenthesis negative 1 comma pi divided by 6 right parenthesis$ on the line $r left parenthesis 3 s i n space theta plus square root of 3 c o s space theta right parenthesis equals 3$ is

The foot of the perpendicular from $left parenthesis negative 1 comma pi divided by 6 right parenthesis$ on the line $r left parenthesis 3 s i n space theta plus square root of 3 c o s space theta right parenthesis equals 3$ is

The equation of the directrix of the conic $2 equals r left parenthesis 3 plus C o s invisible function application theta right parenthesis$ is

The equation of the directrix of the conic $2 equals r left parenthesis 3 plus C o s invisible function application theta right parenthesis$ is

For the circle $r equals 6 C o s space theta$ centre and radius are

For the circle $r equals 6 C o s space theta$ centre and radius are

The equation of the circle with centre at $open parentheses 1 comma 0 to the power of 0 end exponent close parentheses$ , which passes through the point $open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses$ is

The equation of the circle with centre at $open parentheses 1 comma 0 to the power of 0 end exponent close parentheses$ , which passes through the point $open parentheses 0 comma fraction numerator pi over denominator 2 end fraction close parentheses$ is

The centre of the circle $r squared minus 2 r left parenthesis 3 c o s space theta plus 4 s i n space theta right parenthesis minus 24$ is

The centre of the circle $r squared minus 2 r left parenthesis 3 c o s space theta plus 4 s i n space theta right parenthesis minus 24$ is

The centre and radius of the circle $r equals c o s space theta minus s i n space theta$ are respectively

The centre and radius of the circle $r equals c o s space theta minus s i n space theta$ are respectively