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Maths-

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Easy

Question

The polar equation of the circle of radius 5 and touching the initial line at the pole is

$r = 5 s i n θ$
$r = 10 s i n θ$
$r = 5 c o s θ$
$r = 10 c o s θ$

The correct answer is: $r equals 10 s i n space theta$

$T h e space p o l a r space e q u a t i o n space o f space t h e space c i r c l e space w i t h space r a d i u s space a equals 5 space a n d space t o u c h i n g space t h e space i n i t i a l space l i n e space a t space t h e space p o l e space i s r equals 2 a sin theta r equals 2 open parentheses 5 close parentheses sin theta r equals 10 sin theta$

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