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If I = not stretchy integral fraction numerator d x over denominator x square root of 1 minus x to the power of 3 end exponent end root end fraction, then I equals:

  1. 1 third log invisible function application open vertical bar fraction numerator square root of 1 minus x cubed end root minus 1 over denominator square root of 1 minus x cubed end root plus 1 end fraction close vertical bar plus C    
  2. fraction numerator 1 over denominator 3 end fractionlog open vertical bar fraction numerator square root of 1 minus x to the power of 3 end exponent end root plus 1 over denominator square root of 1 minus x to the power of 3 end exponent end root minus 1 end fraction close vertical bar + C    
  3. fraction numerator 2 over denominator 3 end fraction l o g invisible function application open vertical bar 1 minus x to the power of 3 end exponent close vertical bar plus C    
  4. fraction numerator 1 over denominator 3 end fractionlog open vertical bar x to the power of 3 divided by 2 end exponent plus square root of 1 minus x to the power of 3 end exponent end root close vertical bar + C    

The correct answer is: fraction numerator 2 over denominator 3 end fraction l o g invisible function application open vertical bar 1 minus x to the power of 3 end exponent close vertical bar plus C


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