Question

# If then is

- is an integer
- may be fraction
- is an odd number
- an even number

## The correct answer is: an even number

### Related Questions to study

### The free energy change for the following reactions aregivenbelow-C2H2(g)+O2(g)→2CO2(g)+H2O(l);DG°=–1234KJC(s)+O2(g)→CO2(g);DG°=–394KJ H2(g)+O2(g)→H2O(l);DG°=–237KJWhatisthestandardfreeenergychangeforthe reactionH2(g)+2C(s)→C2H2(g)-

### The free energy change for the following reactions aregivenbelow-C2H2(g)+O2(g)→2CO2(g)+H2O(l);DG°=–1234KJC(s)+O2(g)→CO2(g);DG°=–394KJ H2(g)+O2(g)→H2O(l);DG°=–237KJWhatisthestandardfreeenergychangeforthe reactionH2(g)+2C(s)→C2H2(g)-

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### The value of DH–DE for the following reaction at 27°C will be,2NH3(g)→N2(g)+3H2(g)

### If at 298K the bond energies of C–H,C–C,C=C and H–H bonds are respectively 414,347,615and 435KJmol–1,thevalueofenthalpy change for there action H2C=CH2(g)+H2(g)→CH3–CH3(g)at298 K will be-

### If at 298K the bond energies of C–H,C–C,C=C and H–H bonds are respectively 414,347,615and 435KJmol–1,thevalueofenthalpy change for there action H2C=CH2(g)+H2(g)→CH3–CH3(g)at298 K will be-

### If then n=

### If then n=

### There were two women participating in a chess tournament Every participant played two games with the other participants the number of games that the men played between themselves proved to exceed by 66 the number of games that the men played with the women The number of participants is

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### 153 games were played at a chess tournament with each contestant playing once against each of the others The number of participants is

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### If n and are integers such that then n c (n‐l, r‐l)=

### If n and are integers such that then n c (n‐l, r‐l)=

### The least value of the natural number n satisfying

### The least value of the natural number n satisfying

### then (n, r)=

### then (n, r)=

### then ‘n’ is

### then ‘n’ is

### If = mC_{2}, then C_{2} is equal to -

Students must know how to open expressions like nCr.

Also, the value of n! is n.(n−1).(n−2).....3.2.1.

Combination is used to select r objects from n objects when the arrangement of the objects does not matter.

### If = mC_{2}, then C_{2} is equal to -

Students must know how to open expressions like nCr.

Also, the value of n! is n.(n−1).(n−2).....3.2.1.

Combination is used to select r objects from n objects when the arrangement of the objects does not matter.