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text If  end text stack a with rightwards arrow on top equals i plus j minus k comma stack b with rightwards arrow on top equals i minus j plus k comma stack c with rightwards arrow on top is a unit vector such that stack c with rightwards arrow on top times stack a with rightwards arrow on top equals 0 comma left square bracket stack c with rightwards arrow on top stack a with rightwards arrow on top stack b with rightwards arrow on top right square bracket equals0 then a unit vector text end text stack d with rightwards arrow on top perpendicular to text  both  end text stack a with rightwards arrow on top text  and  end text stack c with rightwards arrow on top text end text text is end text

  1. fraction numerator 1 over denominator square root of 6 end fraction left parenthesis 2 i minus j plus k right parenthesis    
  2. fraction numerator 1 over denominator 2 end fraction left parenthesis j plus k right parenthesis    
  3. fraction numerator 1 over denominator square root of 2 end fraction left parenthesis i plus j right parenthesis    
  4. fraction numerator 1 over denominator square root of 2 end fraction left parenthesis i plus k right parenthesis    

The correct answer is: fraction numerator 1 over denominator 2 end fraction left parenthesis j plus k right parenthesis

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