Maths-

General

Easy

Question

# In the adjoining figure, AP and BP are angle bisector of and which meets at P on the parallelogram ABCD. Then =

Hint:

## The correct answer is:

### We should find value of

## If AP and BP are angle bisector, then

$∠1=∠2=∠A/2∠3=∠4=∠B/2$
And Consecutive angles are supplementary
$∴∠1+∠2=180−(∠3+∠4)$
$∠A=180−∠B$
From the figure,
$∠APB=180−(∠1+∠3)$
$=>180−(180−(∠2+∠4))$
$=>∠2+∠4=∠A/2+∠B/2$
$⇒2∠APB=∠A+∠B$
$∠A+∠∠C+∠D$

Hence option 1 is correct

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