In the figure below $stack A B with bar on top parallel to stack D C with bar on top comma stack A E with bar on top parallel to stack B C with bar on top text and end text stack A F with bar on top parallel to stack B D with bar on top$ If $open floor D equals x to the power of ring operator end exponent comma open floor C equals y to the power of 0 end exponent close close$ , $E A B equals k to the power of ring operator end exponent$ and $open floor A B P equals p to the power of ring operator end exponent comma close$ then which of the following is correct ?

So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle x is equal to 105 degrees.

If PQRS is a Square and STR is an Equilateral Triangle. Find the value of a

So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle a is equal to 75 degrees.

If PQRS is a Square and STR is an Equilateral Triangle. Find the value of a

So here we were given a square PQRS and in that an equilateral triangle STR is present. We used the concept of equilateral triangle to solve the answer. So the angle a is equal to 75 degrees.

In a Trapezium ABCD, as shown, $A B parallel to D C comma A D equals D C equals B C equals 20 c m$ and $angle equals 60 º$ then length of AB is

In the following diagram, the bisectors of interior angles of the Parallelogram PQRS enclose a Quadrilateral ABCD. Then find angle A.

In a Rhombus PQRS; if $angle Q S R equals x to the power of ring operator text then ∠ end text P equals$ ?

In an Isosceles Trapezium PQRS, $P R equals left parenthesis 5 x plus 2 right parenthesis text and end text Q S equals left parenthesis 8 x minus 7 right parenthesis c m$ then find the length of PR.

In DABC, if AD is bisector $left floor B A C$ and DE bisects $open floor B D A comma open floor B equals 40 to the power of ring operator end exponent comma ∣ C equals 80 to the power of ring operator end exponent close close$ find $left floor B E D$

Therefore, $angle B E D$ is 85.

In DABC, if AD is bisector $left floor B A C$ and DE bisects $open floor B D A comma open floor B equals 40 to the power of ring operator end exponent comma ∣ C equals 80 to the power of ring operator end exponent close close$ find $left floor B E D$

Therefore, $angle B E D$ is 85.

Find ‘b’ in the given figure

Therefore, the value of b is 125.

Find ‘b’ in the given figure

Therefore, the value of b is 125.

Find x in the given figure

Therefore, the value of x is 65.

Find x in the given figure

Therefore, the value of x is 65.

Find x.

Therefore, the value of X is 70.

Find x.

Therefore, the value of X is 70.

Two circles of the same radii are

So we understood the concept of circles and how they can be equal with the same radii, so Congruent circles are those whose radii are equal.

Two circles of the same radii are

So we understood the concept of circles and how they can be equal with the same radii, so Congruent circles are those whose radii are equal.

The point which divides the line segment joint the points A(7,-6) and B(3,4) in the ratio 1:2 internally lies in the

Here we used the concept of line segment and section formula, the coordinates of the point that splits a line segment (either internally or externally) into a certain ratio are found using the Section formula. Here the x coordinate is positive and y coordinate is negative, so it lies in IV quadrant.

The point which divides the line segment joint the points A(7,-6) and B(3,4) in the ratio 1:2 internally lies in the