The length of the chord joining the points (4cos theta,4sin the-Turito

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Maths-

The length of the chord joining the points $left parenthesis 4 cos invisible function application theta comma blank 4 sin invisible function application theta right parenthesis$ and $left parenthesis 4 cos invisible function application open parentheses theta plus 60 degree close parentheses comma blank 4 sin invisible function application left parenthesis theta plus 60 degree right parenthesis$ of the circle $x to the power of 2 end exponent plus y to the power of 2 end exponent equals 16$ is

Maths-General

4
16
2
8

Answer:The correct answer is: 4

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Assertion (A):If $a > 0, b > 0$ and $c > 0$ , then $(a + b + c) (\frac{1}{a} + \frac{1}{b} + \frac{1}{c}) \geq 9$ Reason (R): For positive numbers $a,$ $b,$ $c,$ $A M \geq G M$

A M \geq G M

= ≻ \frac{\frac{1}{a} + \frac{1}{b} + \frac{1}{c}}{3} \geq (\begin{matrix} 111 \\ - & - \\ \bar{b} a . & c \end{matrix}) \to (1)

D : x^{2} - 3 x - 4 < 0 \supset (x + 1) (x - 4) < 0 \Rightarrow 1 < x < 4

x^{2} - 3 x + 2 > 0 R e j e c t x - 2) (x - 1) > 0 = x < 1 a^{r} x > 2

\frac{(a + b + c)}{3} \geq (a b c)^{\frac{1}{3}} \to (2)

multiply (1) and (2)

Assertion (A):If $a > 0, b > 0$ and $c > 0$ , then $(a + b + c) (\frac{1}{a} + \frac{1}{b} + \frac{1}{c}) \geq 9$ Reason (R): For positive numbers $a,$ $b,$ $c,$ $A M \geq G M$

A M \geq G M

= ≻ \frac{\frac{1}{a} + \frac{1}{b} + \frac{1}{c}}{3} \geq (\begin{matrix} 111 \\ - & - \\ \bar{b} a . & c \end{matrix}) \to (1)

D : x^{2} - 3 x - 4 < 0 \supset (x + 1) (x - 4) < 0 \Rightarrow 1 < x < 4

x^{2} - 3 x + 2 > 0 R e j e c t x - 2) (x - 1) > 0 = x < 1 a^{r} x > 2

\frac{(a + b + c)}{3} \geq (a b c)^{\frac{1}{3}} \to (2)

multiply (1) and (2)

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A 20 $μ F$ capacitor is connected to 45 V battery through a circuit whose resistance is 2000 $Ω .$ What is the final charge on the capacitor?

We know that in steady state the capacitor behaves like as an open circuit

i e

, capacitor will not pass the current.

So, the potential difference across the capacitor = 45 V Hence , the final charge on the capacitor is

q = C V

C = 20 μ F, V = 45 V

∴ q = 20 \times 10^{- 6} \times 45

q = 900 \times 10^{- 6}

q = 9 \times 10^{- 4} C

A 20 $μ F$ capacitor is connected to 45 V battery through a circuit whose resistance is 2000 $Ω .$ What is the final charge on the capacitor?

physics-General

We know that in steady state the capacitor behaves like as an open circuit

i e

, capacitor will not pass the current.

So, the potential difference across the capacitor = 45 V Hence , the final charge on the capacitor is

q = C V

C = 20 μ F, V = 45 V

∴ q = 20 \times 10^{- 6} \times 45

q = 900 \times 10^{- 6}

q = 9 \times 10^{- 4} C

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physics-General

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