Maths-
General
Easy

Question

Observe the following statements and choose correct answer
Statement-I:A particle p moves along a straight line, starting from a fixed point ‘O’, obeying s=16+48t-t to the power of 3 end exponent.the direction of p when t=5 is along Error converting from MathML to accessible text.
Statement-II: For a particle moving on a line, if velocity v<0 then the body moves towards the initial point.

  1. I,II are true, II is correct explanation of I    
  2. I,II are true, II is not correct explanation of I    
  3. I is correct II is false    
  4. I is false II is true    

The correct answer is: I,II are true, II is not correct explanation of I


    Statement -I:

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    Statement ‐ I : The equation zz¯+a¯z+az¯+λ=0 where a is a complex number, represents a circle in Argand plane if λ is real. Statement ‐II : The radius of the circle zz¯+a¯z+az¯+λ=0 is λ-aa¯

    Result    

    Statement ‐ I : The equation zz¯+a¯z+az¯+λ=0 where a is a complex number, represents a circle in Argand plane if λ is real. Statement ‐II : The radius of the circle zz¯+a¯z+az¯+λ=0 is λ-aa¯

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    Result    
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    Divide the following fractions:
    2 over 11 divided by 9 over 22

    Here, we have to divide the given fractions.
    Now, 2/11 ÷ 9/22
    = 2/11 × 22/9
    = 2/1 × 2/9
    = 2 × 2 / 1 × 9
    = 4/9
    Hence, the correct option is (a).

    Divide the following fractions:
    2 over 11 divided by 9 over 22

    GeneralGeneral
    Here, we have to divide the given fractions.
    Now, 2/11 ÷ 9/22
    = 2/11 × 22/9
    = 2/1 × 2/9
    = 2 × 2 / 1 × 9
    = 4/9
    Hence, the correct option is (a).
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    The third cleavage in frog's development is

    The third cleavage in frog's development is

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    The reason why the right kidney is slightly lower than the left is:

    Excretion involves the processes in which substances of no further use or those present in excess qualities are thrown out of the body.

    The reason why the right kidney is slightly lower than the left is:

    biologyGeneral
    Excretion involves the processes in which substances of no further use or those present in excess qualities are thrown out of the body.
    General
    Chemistry-

    Consider the following boron halides
    I) B F subscript 3 end subscript
    II) B C l subscript 3 end subscript
    III) B B r subscript 3 end subscript
    IV) B l subscript 3 end subscript
    The Lewis acid characters of these halides are such that

    Consider the following boron halides
    I) B F subscript 3 end subscript
    II) B C l subscript 3 end subscript
    III) B B r subscript 3 end subscript
    IV) B l subscript 3 end subscript
    The Lewis acid characters of these halides are such that

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    This happens if the proximal convoluted tubule is removed from nephron:

    This happens if the proximal convoluted tubule is removed from nephron:

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    Which is the highest structural organization found in all enzymes?

    Which is the highest structural organization found in all enzymes?

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    The 20 different common amino acids have different-

    The 20 different common amino acids have different-

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    A box contains 100 tickets numbered 1, 2 ...... 100. Two tickets are chosen at random. It is given that the maximum number on the two chosen tickets is not more than 10. The minimum number on them is 5 with probability

    Let A be the event that the maximum number on the two chosen tickets is not more than 10 i.e., the number on them less or equal than 10 and B be the event that the maximum number on them is 5, i.e., the number on them is greater or equal than 5 we have to find P left parenthesis B divided by A right parenthesis.
    Now P left parenthesis B divided by A right parenthesis equals fraction numerator P left parenthesis A intersection B right parenthesis over denominator P left parenthesis A right parenthesis end fraction equals fraction numerator n left parenthesis A intersection B right parenthesis over denominator n left parenthesis A right parenthesis end fraction
    Now the number of ways of getting a number r on the two tickets is the coefficient of x to the power of r end exponent in the expansion of
    left parenthesis x to the power of 1 end exponent plus x to the power of 2 end exponent plus x to the power of 3 end exponent plus........ plus x to the power of 100 end exponent right parenthesis to the power of 2 end exponent equals x to the power of 2 end exponent left parenthesis 1 plus x plus....... plus x to the power of 99 end exponent right parenthesis to the power of 2 end exponent
    equals x to the power of 2 end exponent open parentheses fraction numerator 1 minus x to the power of 100 end exponent over denominator 1 minus x end fraction close parentheses to the power of 2 end exponent equals x to the power of 2 end exponent left parenthesis 1 minus 2 x to the power of 100 end exponent plus x to the power of 200 end exponent right parenthesis left parenthesis 1 minus x right parenthesis to the power of negative 2 end exponent
    equals x to the power of 2 end exponent left parenthesis 1 minus 2 x to the power of 100 end exponent plus x to the power of 200 end exponent right parenthesis left parenthesis 1 plus 2 x plus 3 x to the power of 2 end exponent plus.... plus left parenthesis r plus 1 right parenthesis x to the power of r end exponent plus..... right parenthesis Thus coefficient of x to the power of 2 end exponent equals 1 comma of x to the power of 3 end exponent equals 2 comma of x to the power of 4 end exponent equals 3...... of x to the power of 10 end exponent is 9.
    Hence n left parenthesis A right parenthesis equals 1 plus 2 plus 3 plus 4 plus 5 plus 6 plus 7 plus 8 plus 9 equals 45
    and n left parenthesis A intersection B right parenthesis equals 4 plus 5 plus 6 plus 7 plus 8 plus 9 equals 39
    Hence required probability equals fraction numerator 39 over denominator 45 end fraction equals fraction numerator 13 over denominator 15 end fraction.

    A box contains 100 tickets numbered 1, 2 ...... 100. Two tickets are chosen at random. It is given that the maximum number on the two chosen tickets is not more than 10. The minimum number on them is 5 with probability

    Maths-General
    Let A be the event that the maximum number on the two chosen tickets is not more than 10 i.e., the number on them less or equal than 10 and B be the event that the maximum number on them is 5, i.e., the number on them is greater or equal than 5 we have to find P left parenthesis B divided by A right parenthesis.
    Now P left parenthesis B divided by A right parenthesis equals fraction numerator P left parenthesis A intersection B right parenthesis over denominator P left parenthesis A right parenthesis end fraction equals fraction numerator n left parenthesis A intersection B right parenthesis over denominator n left parenthesis A right parenthesis end fraction
    Now the number of ways of getting a number r on the two tickets is the coefficient of x to the power of r end exponent in the expansion of
    left parenthesis x to the power of 1 end exponent plus x to the power of 2 end exponent plus x to the power of 3 end exponent plus........ plus x to the power of 100 end exponent right parenthesis to the power of 2 end exponent equals x to the power of 2 end exponent left parenthesis 1 plus x plus....... plus x to the power of 99 end exponent right parenthesis to the power of 2 end exponent
    equals x to the power of 2 end exponent open parentheses fraction numerator 1 minus x to the power of 100 end exponent over denominator 1 minus x end fraction close parentheses to the power of 2 end exponent equals x to the power of 2 end exponent left parenthesis 1 minus 2 x to the power of 100 end exponent plus x to the power of 200 end exponent right parenthesis left parenthesis 1 minus x right parenthesis to the power of negative 2 end exponent
    equals x to the power of 2 end exponent left parenthesis 1 minus 2 x to the power of 100 end exponent plus x to the power of 200 end exponent right parenthesis left parenthesis 1 plus 2 x plus 3 x to the power of 2 end exponent plus.... plus left parenthesis r plus 1 right parenthesis x to the power of r end exponent plus..... right parenthesis Thus coefficient of x to the power of 2 end exponent equals 1 comma of x to the power of 3 end exponent equals 2 comma of x to the power of 4 end exponent equals 3...... of x to the power of 10 end exponent is 9.
    Hence n left parenthesis A right parenthesis equals 1 plus 2 plus 3 plus 4 plus 5 plus 6 plus 7 plus 8 plus 9 equals 45
    and n left parenthesis A intersection B right parenthesis equals 4 plus 5 plus 6 plus 7 plus 8 plus 9 equals 39
    Hence required probability equals fraction numerator 39 over denominator 45 end fraction equals fraction numerator 13 over denominator 15 end fraction.
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    All are proteins except –

    All are proteins except –

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    Protein am ion acids are called.

    Protein am ion acids are called.

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    During normal incidence on a glass slab, the angle of incidence = ____.

    • When a ray of light falls on a glass slab normally, the angle between normal and incident ray is zero.
    • Therefore, angle of refraction and emergence will also be zero.
    • So, the correct option is c.

    During normal incidence on a glass slab, the angle of incidence = ____.

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    • When a ray of light falls on a glass slab normally, the angle between normal and incident ray is zero.
    • Therefore, angle of refraction and emergence will also be zero.
    • So, the correct option is c.
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    During refraction through a glass slab, when the medium at the both sides of the glass slab is the same then, the incident ray is parallel to ____.

    • On both the parallel sides of the glass slab, the change in direction of light ray is equal but in opposite directions.
    • Thus, the light ray emerging from the glass slab is parallel to the incident ray.
    • So, the correct option is b.

    During refraction through a glass slab, when the medium at the both sides of the glass slab is the same then, the incident ray is parallel to ____.

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    • On both the parallel sides of the glass slab, the change in direction of light ray is equal but in opposite directions.
    • Thus, the light ray emerging from the glass slab is parallel to the incident ray.
    • So, the correct option is b.
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    Butter is

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    A gel
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    physics-

    To double the volume of a given mass of an ideal gas at 27 ℃ keeping the pressure constant, one must raise the temperature in degree centigrade to

    V proportional to T rightwards double arrow fraction numerator V subscript 1 end subscript over denominator V subscript 2 end subscript end fraction equals fraction numerator T subscript 1 end subscript over denominator T subscript 2 end subscript end fraction rightwards double arrow fraction numerator V over denominator 2 V end fraction equals fraction numerator open parentheses 273 plus 27 close parentheses over denominator T subscript 2 end subscript end fraction equals fraction numerator 300 over denominator T subscript 2 end subscript end fraction
    rightwards double arrow T subscript 2 end subscript equals 600 K equals 327 ℃

    To double the volume of a given mass of an ideal gas at 27 ℃ keeping the pressure constant, one must raise the temperature in degree centigrade to

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    V proportional to T rightwards double arrow fraction numerator V subscript 1 end subscript over denominator V subscript 2 end subscript end fraction equals fraction numerator T subscript 1 end subscript over denominator T subscript 2 end subscript end fraction rightwards double arrow fraction numerator V over denominator 2 V end fraction equals fraction numerator open parentheses 273 plus 27 close parentheses over denominator T subscript 2 end subscript end fraction equals fraction numerator 300 over denominator T subscript 2 end subscript end fraction
    rightwards double arrow T subscript 2 end subscript equals 600 K equals 327 ℃
    parallel

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