The polar equation of y^(2)=4x is -Turito

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Maths-

The polar equation of $y to the power of 2 end exponent equals 4 x$ is

Maths-General

$r = 4 T a n θ S i n θ$
$r = 4 c o s θ S i n θ$
$r = 4 S e c θ C o s e c θ$
$r = 4 C o t θ C o s e c θ$

Answer:The correct answer is: $r equals 4 C o t space theta C o s e c space theta$

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The cartesian equation of $r equals a s i n space 2 theta$ is

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The equation of the line passing through pole and $open parentheses 2 comma fraction numerator pi over denominator 3 end fraction close parentheses$ is

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The polar equation of the straight line passing through $open parentheses 2 comma fraction numerator pi over denominator 6 end fraction close parentheses$ and parallel to the initial line is

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The polar equation of the straight line passing through $open parentheses 6 comma fraction numerator pi over denominator 3 end fraction close parentheses$ and perpendicular to the initial line is

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The angle between the lines $r left square bracket 2 C o s space theta plus 5 S i n space theta right square bracket equals 3$ and $r left square bracket 2 s i n space theta minus 5 C o s space theta right square bracket plus 4 equals 0$ is

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maths-

The number of points in the Cartesian plane with integral co-ordinates satisfying the inequalities |x| $less or equal than$ k, |y| $less or equal than$ k, |x – y| $less or equal than$ k ; is-

|x|

less or equal than

rightwards double arrow

–k

less or equal than

less or equal than

k ….(1)
& |y|

less or equal than

rightwards double arrow

–k

less or equal than

less or equal than

k ….(2)

& |x – y|

less or equal than

rightwards double arrow

|y – x|

less or equal than

rightwards double arrow

–k

less or equal than

y – x

less or equal than

rightwards double arrow

x – k

less or equal than

less or equal than

x + k ….(3)

therefore

Number of points having integral coordinates
= (2k + 1)² – 2
= (3k² + 3k + 1).

The number of points in the Cartesian plane with integral co-ordinates satisfying the inequalities |x| $less or equal than$ k, |y| $less or equal than$ k, |x – y| $less or equal than$ k ; is-

maths-General

|x|

less or equal than

rightwards double arrow

–k

less or equal than

less or equal than

k ….(1)
& |y|

less or equal than

rightwards double arrow

–k

less or equal than

less or equal than

k ….(2)

& |x – y|

less or equal than

rightwards double arrow

|y – x|

less or equal than

rightwards double arrow

–k

less or equal than

y – x

less or equal than

rightwards double arrow

x – k

less or equal than

less or equal than

x + k ….(3)

therefore

Number of points having integral coordinates
= (2k + 1)² – 2
= (3k² + 3k + 1).

General

maths-

A is a set containing n elements. A subset P₁ is chosen, and A is reconstructed by replacing the elements of P₁. The same process is repeated for subsets P₁, P₂, … , P_m, with m > 1. The Number of ways of choosing P₁, P₂, …, P_m so that P₁ $union$ P₂ $union$ … $union$ P_m= A is -

Let A = {a₁, a₂,…..a_n}.
For each a_i (1

less or equal than

less or equal than

n), either a_i

element of

P_j or a_i

not an element of

P_j (1

less or equal than

less or equal than

m) . Thus, there are 2^m choices in which a_i (1

less or equal than

less or equal than

n) may belong to the P_j

apostrophe

s.
Also there is exactly one choice, viz., a_i

not an element of

P_j for j = 1, 2, …, m, for which a_i

not an element of

P₁

union

P₂

union

...

union

P_m.
Therefore, a_i

not an element of

P₁

union

P₂

union

….

union

P_m in (2^m – 1) ways . Since there are n elements in the set A, the number of ways of constructing subsets
P₁, P₂, ….. , P_m is (2^m – 1)ⁿ

A is a set containing n elements. A subset P₁ is chosen, and A is reconstructed by replacing the elements of P₁. The same process is repeated for subsets P₁, P₂, … , P_m, with m > 1. The Number of ways of choosing P₁, P₂, …, P_m so that P₁ $union$ P₂ $union$ … $union$ P_m= A is -

maths-General

Let A = {a₁, a₂,…..a_n}.
For each a_i (1

less or equal than

less or equal than

n), either a_i

element of

P_j or a_i

not an element of

P_j (1

less or equal than

less or equal than

m) . Thus, there are 2^m choices in which a_i (1

less or equal than

less or equal than

n) may belong to the P_j

apostrophe

s.
Also there is exactly one choice, viz., a_i

not an element of

P_j for j = 1, 2, …, m, for which a_i

not an element of

P₁

union

P₂

union

...

union

P_m.
Therefore, a_i

not an element of

P₁

union

P₂

union

….

union

P_m in (2^m – 1) ways . Since there are n elements in the set A, the number of ways of constructing subsets
P₁, P₂, ….. , P_m is (2^m – 1)ⁿ

General

physics-

Two tuning forks $P$ and $Q$ are vibrated together. The number of beats produced are represented by the straight line $O A$ in the following graph. After loading $Q$ with wax again these are vibrated together and the beats produced are represented by the line $O B.$ If the frequency of $P$ is $341 H z comma$ the frequency of $Q$ will be

n subscript Q end subscript equals 341 plus-or-minus 3 equals 344 H z

338 H z

On waxing

Q comma

the number of beats decreases hence

n subscript Q end subscript equals 344 H z

Two tuning forks $P$ and $Q$ are vibrated together. The number of beats produced are represented by the straight line $O A$ in the following graph. After loading $Q$ with wax again these are vibrated together and the beats produced are represented by the line $O B.$ If the frequency of $P$ is $341 H z comma$ the frequency of $Q$ will be

physics-General

n subscript Q end subscript equals 341 plus-or-minus 3 equals 344 H z

338 H z

On waxing

Q comma

the number of beats decreases hence

n subscript Q end subscript equals 344 H z

General

maths-

If a hyperbola passing through the origin has $3 x minus 4 y minus 1 equals 0$ and $4 x minus 3 y minus 6 equals 0$ as its asymptotes, then the equation of its tranvsverse and conjugate axes are

maths-General

General

physics-

Which of the following curves represents correctly the oscillation given by $y equals y subscript 0 end subscript sin invisible function application open parentheses omega t minus ϕ close parentheses comma blank w h e r e blank 0 less than ϕ less than 90$

Given equation

y equals y subscript 0 end subscript sin invisible function application left parenthesis omega t minus ϕ right parenthesis

t equals 0 comma blank y equals negative y subscript 0 end subscript sin invisible function application ϕ

This is case with curve marked

D

Which of the following curves represents correctly the oscillation given by $y equals y subscript 0 end subscript sin invisible function application open parentheses omega t minus ϕ close parentheses comma blank w h e r e blank 0 less than ϕ less than 90$

physics-General

Given equation

y equals y subscript 0 end subscript sin invisible function application left parenthesis omega t minus ϕ right parenthesis

t equals 0 comma blank y equals negative y subscript 0 end subscript sin invisible function application ϕ

This is case with curve marked

D

General

maths-

In a triangle ABC, if a : b : c = 7 : 8 : 9, then cos A : cos B equals to

maths-General

General

physics-

A small source of sound moves on a circle as shown in the figure and an observer is standing on $O.$ Let $n subscript 1 end subscript comma n subscript 2 end subscript$ and $n subscript 3 end subscript$ be the frequencies heard when the source is at $A comma blank B blank$ and $C$ respectively. Then

At point

A comma

source is moving away from observer so apparent frequency

n subscript 1 end subscript less than n

(actual frequency) At point

B

source is coming towards observer so apparent frequency

n subscript 2 end subscript greater than n

and point

C

source is moving perpendicular to observer so

n subscript 3 end subscript equals n

Hence

n subscript 2 end subscript greater than n subscript 3 end subscript greater than n subscript 1 end subscript

A small source of sound moves on a circle as shown in the figure and an observer is standing on $O.$ Let $n subscript 1 end subscript comma n subscript 2 end subscript$ and $n subscript 3 end subscript$ be the frequencies heard when the source is at $A comma blank B blank$ and $C$ respectively. Then

physics-General

At point

A comma

source is moving away from observer so apparent frequency

n subscript 1 end subscript less than n

(actual frequency) At point

B

source is coming towards observer so apparent frequency

n subscript 2 end subscript greater than n

and point

C

source is moving perpendicular to observer so

n subscript 3 end subscript equals n

Hence

n subscript 2 end subscript greater than n subscript 3 end subscript greater than n subscript 1 end subscript

General

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The polar equation of $y to the power of 2 end exponent equals 4 x$ is

$r = 4 T a n θ S i n θ$
$r = 4 c o s θ S i n θ$
$r = 4 S e c θ C o s e c θ$
$r = 4 C o t θ C o s e c θ$

Answer:The correct answer is: $r equals 4 C o t space theta C o s e c space theta$

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Which of the following curves represents correctly the oscillation given by $y equals y subscript 0 end subscript sin invisible function application open parentheses omega t minus ϕ close parentheses comma blank w h e r e blank 0 less than ϕ less than 90$

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A small source of sound moves on a circle as shown in the figure and an observer is standing on $O.$ Let $n subscript 1 end subscript comma n subscript 2 end subscript$ and $n subscript 3 end subscript$ be the frequencies heard when the source is at $A comma blank B blank$ and $C$ respectively. Then

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The polar equation of is

Answer:The correct answer is:

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A is a set containing n elements. A subset P1 is chosen, and A is reconstructed by replacing the elements of P1. The same process is repeated for subsets P1, P2, … , Pm, with m > 1. The Number of ways of choosing P1, P2, …, Pm so that P1 P2 … Pm= A is -

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The polar equation of $y to the power of 2 end exponent equals 4 x$ is

Answer:The correct answer is: $r equals 4 C o t space theta C o s e c space theta$

The cartesian equation of $r equals a s i n space 2 theta$ is

The cartesian equation of $r equals a s i n space 2 theta$ is

The equation of the line passing through pole and $open parentheses 2 comma fraction numerator pi over denominator 3 end fraction close parentheses$ is

The equation of the line passing through pole and $open parentheses 2 comma fraction numerator pi over denominator 3 end fraction close parentheses$ is

The polar equation of the straight line passing through $open parentheses 2 comma fraction numerator pi over denominator 6 end fraction close parentheses$ and parallel to the initial line is

The polar equation of the straight line passing through $open parentheses 2 comma fraction numerator pi over denominator 6 end fraction close parentheses$ and parallel to the initial line is

The polar equation of the straight line passing through $open parentheses 6 comma fraction numerator pi over denominator 3 end fraction close parentheses$ and perpendicular to the initial line is

The polar equation of the straight line passing through $open parentheses 6 comma fraction numerator pi over denominator 3 end fraction close parentheses$ and perpendicular to the initial line is

The angle between the lines $r left square bracket 2 C o s space theta plus 5 S i n space theta right square bracket equals 3$ and $r left square bracket 2 s i n space theta minus 5 C o s space theta right square bracket plus 4 equals 0$ is

The angle between the lines $r left square bracket 2 C o s space theta plus 5 S i n space theta right square bracket equals 3$ and $r left square bracket 2 s i n space theta minus 5 C o s space theta right square bracket plus 4 equals 0$ is

The number of points in the Cartesian plane with integral co-ordinates satisfying the inequalities |x| $less or equal than$ k, |y| $less or equal than$ k, |x – y| $less or equal than$ k ; is-

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If a hyperbola passing through the origin has $3 x minus 4 y minus 1 equals 0$ and $4 x minus 3 y minus 6 equals 0$ as its asymptotes, then the equation of its tranvsverse and conjugate axes are

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Which of the following curves represents correctly the oscillation given by $y equals y subscript 0 end subscript sin invisible function application open parentheses omega t minus ϕ close parentheses comma blank w h e r e blank 0 less than ϕ less than 90$

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(Area of $increment$ GPL) to (Area of $increment$ ALD) is equal to

(Area of $increment$ GPL) to (Area of $increment$ ALD) is equal to