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# A body of mass slides down a curved track which is quadrant of a circle of radius . All the surfaces are frictionless. If the body starts from rest, its speed at the bottom of the track is

## The correct answer is:

### By conservation of energy,

### Related Questions to study

physics-

### A 10 kg brick moves along an -axis. Its acceleration as a function of its position is shown in figure. What is the net work performed on the brick by the force causing the acceleration as the brick moves from to m?

According to the graph the acceleration varies linearly with the coordinate . We may write , where is the slope of the graph.

From the graph

The force on the brick is in the positive -direction and according to Newton’s second law, its magnitude is given by

If is the final coordinate, the work done by the force is

From the graph

The force on the brick is in the positive -direction and according to Newton’s second law, its magnitude is given by

If is the final coordinate, the work done by the force is

### A 10 kg brick moves along an -axis. Its acceleration as a function of its position is shown in figure. What is the net work performed on the brick by the force causing the acceleration as the brick moves from to m?

physics-General

According to the graph the acceleration varies linearly with the coordinate . We may write , where is the slope of the graph.

From the graph

The force on the brick is in the positive -direction and according to Newton’s second law, its magnitude is given by

If is the final coordinate, the work done by the force is

From the graph

The force on the brick is in the positive -direction and according to Newton’s second law, its magnitude is given by

If is the final coordinate, the work done by the force is

physics-

### Force on a particle moving in a straight line varies with distance as shown in the figure. The work done on the particle during its displacement of

Work = Area under graph

### Force on a particle moving in a straight line varies with distance as shown in the figure. The work done on the particle during its displacement of

physics-General

Work = Area under graph

physics-

### The potential energy of a system is represented in the first figure. The force acting on the system will be represented by

As slope of problem graph is positive and constant upto certain distance and then it becomes zero

So from , up to distance ,

constant (negative) and becomes zero suddenly

So from , up to distance ,

constant (negative) and becomes zero suddenly

### The potential energy of a system is represented in the first figure. The force acting on the system will be represented by

physics-General

As slope of problem graph is positive and constant upto certain distance and then it becomes zero

So from , up to distance ,

constant (negative) and becomes zero suddenly

So from , up to distance ,

constant (negative) and becomes zero suddenly

physics-

### The work done by force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is

Work done

ABCD +Area CEFD

ABCD +Area CEFD

### The work done by force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is

physics-General

Work done

ABCD +Area CEFD

ABCD +Area CEFD

physics-

### Two rectangular blocks and of masses 2kg and 3 kg respectively are connected by spring of spring constant 10.8 and are placed on a frictionless horizontal surface. The block was given an initial velocity of 0.15 in the direction shown in the figure. The maximum compression of the spring during the motion is

As the block A moves with velocity with velocity 0.15 , it compresses the spring Which pushes B towards right. A goes on compressing the spring till the velocity acquired by B becomes equal to the velocity of A, i.e. 0.15 . Let this velocity be v. Now, spring is in a state of maximum compression. Let x be the maximum compression at this stage.

According to the law of conservation of linear momentum, we get

Or

According to the law of conservation of energy

Or

According to the law of conservation of linear momentum, we get

Or

According to the law of conservation of energy

Or

### Two rectangular blocks and of masses 2kg and 3 kg respectively are connected by spring of spring constant 10.8 and are placed on a frictionless horizontal surface. The block was given an initial velocity of 0.15 in the direction shown in the figure. The maximum compression of the spring during the motion is

physics-General

As the block A moves with velocity with velocity 0.15 , it compresses the spring Which pushes B towards right. A goes on compressing the spring till the velocity acquired by B becomes equal to the velocity of A, i.e. 0.15 . Let this velocity be v. Now, spring is in a state of maximum compression. Let x be the maximum compression at this stage.

According to the law of conservation of linear momentum, we get

Or

According to the law of conservation of energy

Or

According to the law of conservation of linear momentum, we get

Or

According to the law of conservation of energy

Or

physics-

### Six identical balls are linked in a straight groove made on a horizontal frictionless surface as shown. Two similar balls each moving with a velocity collide elastically with the row of 6 balls from left. What will happen

Momentum and kinetic energy is conserved only in this case

### Six identical balls are linked in a straight groove made on a horizontal frictionless surface as shown. Two similar balls each moving with a velocity collide elastically with the row of 6 balls from left. What will happen

physics-General

Momentum and kinetic energy is conserved only in this case

physics-

### A force acting on an object varies with distance as shown here. The force is in and in . The work done by the force in moving the object from to is

Work done = Area enclosed by graph

### A force acting on an object varies with distance as shown here. The force is in and in . The work done by the force in moving the object from to is

physics-General

Work done = Area enclosed by graph

physics-

### What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of (Take )

### What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of (Take )

physics-General

physics-

### The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant k and compresses it by length L. The maximum momentum of the block after collides is

Momentum would be maximum when KE would be maximum and this is the case when total elastic PE is converted KE.

According to conservation of energy

Or

According to conservation of energy

Or

### The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant k and compresses it by length L. The maximum momentum of the block after collides is

physics-General

Momentum would be maximum when KE would be maximum and this is the case when total elastic PE is converted KE.

According to conservation of energy

Or

According to conservation of energy

Or

physics

### The area covered by the curve of V-t graph and time axis is equal to magnitude of

### The area covered by the curve of V-t graph and time axis is equal to magnitude of

physicsGeneral

physics-

### In a children’s park, there is a slide which has a total length of 10 m and a height of 8.0 m. A vertical ladder is provided to reach the top. A boy weighing 200 N climbs up the ladder to the top of the slide and slides down to the ground. The average friction offered by the slide is three-tenth of his weight. The work done by the slide on the boy as he comes down is

or

### In a children’s park, there is a slide which has a total length of 10 m and a height of 8.0 m. A vertical ladder is provided to reach the top. A boy weighing 200 N climbs up the ladder to the top of the slide and slides down to the ground. The average friction offered by the slide is three-tenth of his weight. The work done by the slide on the boy as he comes down is

physics-General

or

physics-

### A mass ‘m’ moves with a velocity 'v’ and collides in elastically with another identical mass. After collision the Ist mass moves with velocity in a direction perpendicular to the initial direction of motion. Find the speed of the 2^{nd} mass after collision

Let mass moves with velocity and collides inelastically with mass which is at rest

According to problem mass moves in a perpendicular direction and let the mass moves at angle with the horizontal with velocity

Initial horizontal momentum of system

(before collision) ….(i)

Final horizontal momentum of system

(after collision) ….(ii)

From the conservation of horizontal linear momentum

…(iii)

Initial vertical momentum of system (before collision) is zero

Final vertical momentum of system

From the conservation of vertical linear momentum

…(iv)

By solving (iii) and (iv)

According to problem mass moves in a perpendicular direction and let the mass moves at angle with the horizontal with velocity

Initial horizontal momentum of system

(before collision) ….(i)

Final horizontal momentum of system

(after collision) ….(ii)

From the conservation of horizontal linear momentum

…(iii)

Initial vertical momentum of system (before collision) is zero

Final vertical momentum of system

From the conservation of vertical linear momentum

…(iv)

By solving (iii) and (iv)

### A mass ‘m’ moves with a velocity 'v’ and collides in elastically with another identical mass. After collision the Ist mass moves with velocity in a direction perpendicular to the initial direction of motion. Find the speed of the 2^{nd} mass after collision

physics-General

Let mass moves with velocity and collides inelastically with mass which is at rest

According to problem mass moves in a perpendicular direction and let the mass moves at angle with the horizontal with velocity

Initial horizontal momentum of system

(before collision) ….(i)

Final horizontal momentum of system

(after collision) ….(ii)

From the conservation of horizontal linear momentum

…(iii)

Initial vertical momentum of system (before collision) is zero

Final vertical momentum of system

From the conservation of vertical linear momentum

…(iv)

By solving (iii) and (iv)

According to problem mass moves in a perpendicular direction and let the mass moves at angle with the horizontal with velocity

Initial horizontal momentum of system

(before collision) ….(i)

Final horizontal momentum of system

(after collision) ….(ii)

From the conservation of horizontal linear momentum

…(iii)

Initial vertical momentum of system (before collision) is zero

Final vertical momentum of system

From the conservation of vertical linear momentum

…(iv)

By solving (iii) and (iv)

physics-

### A toy car of mass 5 kg moves up a ramp under the influence of force plotted against displacement . The maximum height attained is given by

Work done = Gain in potential energy

Area under curve

Area under curve

### A toy car of mass 5 kg moves up a ramp under the influence of force plotted against displacement . The maximum height attained is given by

physics-General

Work done = Gain in potential energy

Area under curve

Area under curve

physics

### In uniformly accelerated motion the slope of velocity - time graph gives ....

### In uniformly accelerated motion the slope of velocity - time graph gives ....

physicsGeneral

physics

### The graph of displacement (x) time (t) for an object is given in the figure. In which part of the graph the acceleration of the particle is positive ?

### The graph of displacement (x) time (t) for an object is given in the figure. In which part of the graph the acceleration of the particle is positive ?

physicsGeneral