Physics-
The work done by force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is

Physics-General
- 225 J
- 200 J
- 400 J
- 175 J
Answer:The correct answer is: 200 JWork done 
ABCD +Area CEFD



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physics-
The potential energy of a system is represented in the first figure. The force acting on the system will be represented by

As slope of problem graph is positive and constant upto certain distance and then it becomes zero
So from
, up to distance
,
constant (negative) and becomes zero suddenly
So from
The potential energy of a system is represented in the first figure. The force acting on the system will be represented by

physics-General
As slope of problem graph is positive and constant upto certain distance and then it becomes zero
So from
, up to distance
,
constant (negative) and becomes zero suddenly
So from
physics-
Force
on a particle moving in a straight line varies with distance
as shown in the figure. The work done on the particle during its displacement of 

Work = Area under
graph

Force
on a particle moving in a straight line varies with distance
as shown in the figure. The work done on the particle during its displacement of 

physics-General
Work = Area under
graph

physics-
A 10 kg brick moves along an
-axis. Its acceleration as a function of its position is shown in figure. What is the net work performed on the brick by the force causing the acceleration as the brick moves from
to
m?

According to the graph the acceleration
varies linearly with the coordinate
. We may write
, where
is the slope of the graph.
From the graph

The force on the brick is in the positive
-direction and according to Newton’s second law, its magnitude is given by

If
is the final coordinate, the work done by the force is



From the graph
The force on the brick is in the positive
If
A 10 kg brick moves along an
-axis. Its acceleration as a function of its position is shown in figure. What is the net work performed on the brick by the force causing the acceleration as the brick moves from
to
m?

physics-General
According to the graph the acceleration
varies linearly with the coordinate
. We may write
, where
is the slope of the graph.
From the graph

The force on the brick is in the positive
-direction and according to Newton’s second law, its magnitude is given by

If
is the final coordinate, the work done by the force is



From the graph
The force on the brick is in the positive
If
physics-
A body of mass
slides down a curved track which is quadrant of a circle of radius
. All the surfaces are frictionless. If the body starts from rest, its speed at the bottom of the track is

By conservation of energy, 

A body of mass
slides down a curved track which is quadrant of a circle of radius
. All the surfaces are frictionless. If the body starts from rest, its speed at the bottom of the track is

physics-General
By conservation of energy, 

physics-
In the given curved road, if particle is released from
then

If the surface is smooth then the kinetic energy at
never be zero
If the surface is rough, the kinetic energy at
be zero. Because, work done by force of friction is negative. If work done by friction is equal to
then, net work done on body will be zero. Hence, net change in kinetic energy is zero. Hence, (b) is correct If the surface is rough, the kinetic energy at
must be lesser than
. If surface is smooth, the kinetic energy at
is equal to
The reason is same as in (a) and (b)
If the surface is rough, the kinetic energy at
In the given curved road, if particle is released from
then

physics-General
If the surface is smooth then the kinetic energy at
never be zero
If the surface is rough, the kinetic energy at
be zero. Because, work done by force of friction is negative. If work done by friction is equal to
then, net work done on body will be zero. Hence, net change in kinetic energy is zero. Hence, (b) is correct If the surface is rough, the kinetic energy at
must be lesser than
. If surface is smooth, the kinetic energy at
is equal to
The reason is same as in (a) and (b)
If the surface is rough, the kinetic energy at
physics-
The relation between the displacement
of an object produced by the application of the variable force
is represented by a graph shown in the figure. If the object undergoes a displacement from
to
the work done will be approximately equal to

Work done = Area under curve and displacement axis
= Area of trapezium


As the area actually is not trapezium so work done will be more than
approximately 
= Area of trapezium
As the area actually is not trapezium so work done will be more than
The relation between the displacement
of an object produced by the application of the variable force
is represented by a graph shown in the figure. If the object undergoes a displacement from
to
the work done will be approximately equal to

physics-General
Work done = Area under curve and displacement axis
= Area of trapezium


As the area actually is not trapezium so work done will be more than
approximately 
= Area of trapezium
As the area actually is not trapezium so work done will be more than
physics-
Two rectangular blocks
and
of masses 2kg and 3 kg respectively are connected by spring of spring constant 10.8
and are placed on a frictionless horizontal surface. The block
was given an initial velocity of 0.15
in the direction shown in the figure. The maximum compression of the spring during the motion is

As the block A moves with velocity with velocity 0.15
, it compresses the spring Which pushes B towards right. A goes on compressing the spring till the velocity acquired by B becomes equal to the velocity of A, i.e. 0.15
. Let this velocity be v. Now, spring is in a state of maximum compression. Let x be the maximum compression at this stage.

According to the law of conservation of linear momentum, we get

Or

According to the law of conservation of energy




According to the law of conservation of linear momentum, we get
Or
According to the law of conservation of energy