Physics-
General
Easy

Question

The work done by force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is

  1. 225 J    
  2. 200 J    
  3. 400 J    
  4. 175 J    

The correct answer is: 200 J


    Work done W equals A r e a blank A B C E F D A
    equals A r e aABCD +Area CEFD

    equals fraction numerator 1 over denominator 2 end fraction cross times open parentheses 15 plus 10 close parentheses cross times 10 plus fraction numerator 1 over denominator 2 end fraction cross times left parenthesis 10 plus 20 right parenthesis cross times 5
    equals 125 plus 75 equals 200 J

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