Physics-
The work done by force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is
Physics-General
- 225 J
- 200 J
- 400 J
- 175 J
Answer:The correct answer is: 200 JWork done 
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physics-
The potential energy of a system is represented in the first figure. The force acting on the system will be represented by
As slope of problem graph is positive and constant upto certain distance and then it becomes zero
So from
, up to distance 
,
constant (negative) and becomes zero suddenly
So from
, up to distance , constant (negative) and becomes zero suddenlyThe potential energy of a system is represented in the first figure. The force acting on the system will be represented by
physics-General
As slope of problem graph is positive and constant upto certain distance and then it becomes zero
So from, up to distance ,
constant (negative) and becomes zero suddenly
So from
, up to distance , constant (negative) and becomes zero suddenlyphysics-
Force 
on a particle moving in a straight line varies with distance 
as shown in the figure. The work done on the particle during its displacement of 
Work = Area under 
graph
graphForce on a particle moving in a straight line varies with distance as shown in the figure. The work done on the particle during its displacement of
physics-General
Work = Area under graph
graphphysics-
A 10 kg brick moves along an 
-axis. Its acceleration as a function of its position is shown in figure. What is the net work performed on the brick by the force causing the acceleration as the brick moves from 
to 
m?
According to the graph the acceleration varies linearly with the coordinate . We may write 
, where 
is the slope of the graph.
From the graph
The force on the brick is in the positive-direction and according to Newton’s second law, its magnitude is given by
If
is the final coordinate, the work done by the force is
varies linearly with the coordinate . We may write , where is the slope of the graph.From the graph
The force on the brick is in the positive
-direction and according to Newton’s second law, its magnitude is given byIf
is the final coordinate, the work done by the force isA 10 kg brick moves along an -axis. Its acceleration as a function of its position is shown in figure. What is the net work performed on the brick by the force causing the acceleration as the brick moves from to m?
physics-General
According to the graph the acceleration varies linearly with the coordinate . We may write , where is the slope of the graph.
From the graph
The force on the brick is in the positive-direction and according to Newton’s second law, its magnitude is given by
If is the final coordinate, the work done by the force is
varies linearly with the coordinate . We may write , where is the slope of the graph.From the graph
The force on the brick is in the positive
-direction and according to Newton’s second law, its magnitude is given byIf
is the final coordinate, the work done by the force isphysics-
A body of mass 
slides down a curved track which is quadrant of a circle of radius 
. All the surfaces are frictionless. If the body starts from rest, its speed at the bottom of the track is
By conservation of energy, 
A body of mass slides down a curved track which is quadrant of a circle of radius . All the surfaces are frictionless. If the body starts from rest, its speed at the bottom of the track is
physics-General
By conservation of energy,
physics-
In the given curved road, if particle is released from 
then
If the surface is smooth then the kinetic energy at 
never be zero
If the surface is rough, the kinetic energy at be zero. Because, work done by force of friction is negative. If work done by friction is equal to 
then, net work done on body will be zero. Hence, net change in kinetic energy is zero. Hence, (b) is correct If the surface is rough, the kinetic energy at must be lesser than . If surface is smooth, the kinetic energy at is equal to The reason is same as in (a) and (b)
never be zeroIf the surface is rough, the kinetic energy at
be zero. Because, work done by force of friction is negative. If work done by friction is equal to then, net work done on body will be zero. Hence, net change in kinetic energy is zero. Hence, (b) is correct If the surface is rough, the kinetic energy at must be lesser than . If surface is smooth, the kinetic energy at is equal to The reason is same as in (a) and (b)In the given curved road, if particle is released from then
physics-General
If the surface is smooth then the kinetic energy at never be zero
If the surface is rough, the kinetic energy at be zero. Because, work done by force of friction is negative. If work done by friction is equal to then, net work done on body will be zero. Hence, net change in kinetic energy is zero. Hence, (b) is correct If the surface is rough, the kinetic energy at must be lesser than . If surface is smooth, the kinetic energy at is equal to The reason is same as in (a) and (b)
never be zeroIf the surface is rough, the kinetic energy at
be zero. Because, work done by force of friction is negative. If work done by friction is equal to then, net work done on body will be zero. Hence, net change in kinetic energy is zero. Hence, (b) is correct If the surface is rough, the kinetic energy at must be lesser than . If surface is smooth, the kinetic energy at is equal to The reason is same as in (a) and (b)physics-
The relation between the displacement 
of an object produced by the application of the variable force is represented by a graph shown in the figure. If the object undergoes a displacement from 
to 
the work done will be approximately equal to
Work done = Area under curve and displacement axis
= Area of trapezium
As the area actually is not trapezium so work done will be more than
approximately 
= Area of trapezium
As the area actually is not trapezium so work done will be more than
approximately The relation between the displacement of an object produced by the application of the variable force is represented by a graph shown in the figure. If the object undergoes a displacement from to the work done will be approximately equal to
physics-General
Work done = Area under curve and displacement axis
= Area of trapezium
As the area actually is not trapezium so work done will be more than approximately
= Area of trapezium
As the area actually is not trapezium so work done will be more than
approximately physics-
Two rectangular blocks 
and 
of masses 2kg and 3 kg respectively are connected by spring of spring constant 10.8 
and are placed on a frictionless horizontal surface. The block was given an initial velocity of 0.15 
in the direction shown in the figure. The maximum compression of the spring during the motion is
As the block A moves with velocity with velocity 0.15 , it compresses the spring Which pushes B towards right. A goes on compressing the spring till the velocity acquired by B becomes equal to the velocity of A, i.e. 0.15 . Let this velocity be v. Now, spring is in a state of maximum compression. Let x be the maximum compression at this stage.
According to the law of conservation of linear momentum, we get
Or
According to the law of conservation of energy
, it compresses the spring Which pushes B towards right. A goes on compressing the spring till the velocity acquired by B becomes equal to the velocity of A, i.e. 0.15 . Let this velocity be v. Now, spring is in a state of maximum compression. Let x be the maximum compression at this stage.According to the law of conservation of linear momentum, we get
Or
According to the law of conservation of energy