Physics-

General

Easy

Question

# The work done by force acting on a body is as shown in the graph. The total work done in covering an initial distance of 20 m is

- 225 J
- 200 J
- 400 J
- 175 J

## The correct answer is: 200 J

### Work done

ABCD +Area CEFD

### Related Questions to study

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### Two rectangular blocks and of masses 2kg and 3 kg respectively are connected by spring of spring constant 10.8 and are placed on a frictionless horizontal surface. The block was given an initial velocity of 0.15 in the direction shown in the figure. The maximum compression of the spring during the motion is

As the block A moves with velocity with velocity 0.15 , it compresses the spring Which pushes B towards right. A goes on compressing the spring till the velocity acquired by B becomes equal to the velocity of A, i.e. 0.15 . Let this velocity be v. Now, spring is in a state of maximum compression. Let x be the maximum compression at this stage.

According to the law of conservation of linear momentum, we get

Or

According to the law of conservation of energy

Or

According to the law of conservation of linear momentum, we get

Or

According to the law of conservation of energy

Or

### Two rectangular blocks and of masses 2kg and 3 kg respectively are connected by spring of spring constant 10.8 and are placed on a frictionless horizontal surface. The block was given an initial velocity of 0.15 in the direction shown in the figure. The maximum compression of the spring during the motion is

physics-General

As the block A moves with velocity with velocity 0.15 , it compresses the spring Which pushes B towards right. A goes on compressing the spring till the velocity acquired by B becomes equal to the velocity of A, i.e. 0.15 . Let this velocity be v. Now, spring is in a state of maximum compression. Let x be the maximum compression at this stage.

According to the law of conservation of linear momentum, we get

Or

According to the law of conservation of energy

Or

According to the law of conservation of linear momentum, we get

Or

According to the law of conservation of energy

Or

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### Six identical balls are linked in a straight groove made on a horizontal frictionless surface as shown. Two similar balls each moving with a velocity collide elastically with the row of 6 balls from left. What will happen

Momentum and kinetic energy is conserved only in this case

### Six identical balls are linked in a straight groove made on a horizontal frictionless surface as shown. Two similar balls each moving with a velocity collide elastically with the row of 6 balls from left. What will happen

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Momentum and kinetic energy is conserved only in this case

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### A force acting on an object varies with distance as shown here. The force is in and in . The work done by the force in moving the object from to is

Work done = Area enclosed by graph

### A force acting on an object varies with distance as shown here. The force is in and in . The work done by the force in moving the object from to is

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Work done = Area enclosed by graph

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### What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of (Take )

### What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of (Take )

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### The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant k and compresses it by length L. The maximum momentum of the block after collides is

Momentum would be maximum when KE would be maximum and this is the case when total elastic PE is converted KE.

According to conservation of energy

Or

According to conservation of energy

Or

### The block of mass M moving on the frictionless horizontal surface collides with the spring of spring constant k and compresses it by length L. The maximum momentum of the block after collides is

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Momentum would be maximum when KE would be maximum and this is the case when total elastic PE is converted KE.

According to conservation of energy

Or

According to conservation of energy

Or

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### The area covered by the curve of V-t graph and time axis is equal to magnitude of

### The area covered by the curve of V-t graph and time axis is equal to magnitude of

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### In a children’s park, there is a slide which has a total length of 10 m and a height of 8.0 m. A vertical ladder is provided to reach the top. A boy weighing 200 N climbs up the ladder to the top of the slide and slides down to the ground. The average friction offered by the slide is three-tenth of his weight. The work done by the slide on the boy as he comes down is

or

### In a children’s park, there is a slide which has a total length of 10 m and a height of 8.0 m. A vertical ladder is provided to reach the top. A boy weighing 200 N climbs up the ladder to the top of the slide and slides down to the ground. The average friction offered by the slide is three-tenth of his weight. The work done by the slide on the boy as he comes down is

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or

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### A mass ‘m’ moves with a velocity 'v’ and collides in elastically with another identical mass. After collision the Ist mass moves with velocity in a direction perpendicular to the initial direction of motion. Find the speed of the 2^{nd} mass after collision

Let mass moves with velocity and collides inelastically with mass which is at rest

According to problem mass moves in a perpendicular direction and let the mass moves at angle with the horizontal with velocity

Initial horizontal momentum of system

(before collision) ….(i)

Final horizontal momentum of system

(after collision) ….(ii)

From the conservation of horizontal linear momentum

…(iii)

Initial vertical momentum of system (before collision) is zero

Final vertical momentum of system

From the conservation of vertical linear momentum

…(iv)

By solving (iii) and (iv)

According to problem mass moves in a perpendicular direction and let the mass moves at angle with the horizontal with velocity

Initial horizontal momentum of system

(before collision) ….(i)

Final horizontal momentum of system

(after collision) ….(ii)

From the conservation of horizontal linear momentum

…(iii)

Initial vertical momentum of system (before collision) is zero

Final vertical momentum of system

From the conservation of vertical linear momentum

…(iv)

By solving (iii) and (iv)

### A mass ‘m’ moves with a velocity 'v’ and collides in elastically with another identical mass. After collision the Ist mass moves with velocity in a direction perpendicular to the initial direction of motion. Find the speed of the 2^{nd} mass after collision

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Let mass moves with velocity and collides inelastically with mass which is at rest

According to problem mass moves in a perpendicular direction and let the mass moves at angle with the horizontal with velocity

Initial horizontal momentum of system

(before collision) ….(i)

Final horizontal momentum of system

(after collision) ….(ii)

From the conservation of horizontal linear momentum

…(iii)

Initial vertical momentum of system (before collision) is zero

Final vertical momentum of system

From the conservation of vertical linear momentum

…(iv)

By solving (iii) and (iv)

According to problem mass moves in a perpendicular direction and let the mass moves at angle with the horizontal with velocity

Initial horizontal momentum of system

(before collision) ….(i)

Final horizontal momentum of system

(after collision) ….(ii)

From the conservation of horizontal linear momentum

…(iii)

Initial vertical momentum of system (before collision) is zero

Final vertical momentum of system

From the conservation of vertical linear momentum

…(iv)

By solving (iii) and (iv)

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### A toy car of mass 5 kg moves up a ramp under the influence of force plotted against displacement . The maximum height attained is given by

Work done = Gain in potential energy

Area under curve

Area under curve

### A toy car of mass 5 kg moves up a ramp under the influence of force plotted against displacement . The maximum height attained is given by

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Work done = Gain in potential energy

Area under curve

Area under curve

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### In uniformly accelerated motion the slope of velocity - time graph gives ....

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### The graph of displacement (x) time (t) for an object is given in the figure. In which part of the graph the acceleration of the particle is positive ?

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### In the above figure acceleration (a) time (t) graph is given. Hence

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### A block of mass 2kg is free to move along the x- axis. It is at rest and from t=0 onwards it is subjected to a time-dependent force in the x- direction. The force varies with t as shown in the figure. The kinetic energy of the block after 4.5 seconds is

### A block of mass 2kg is free to move along the x- axis. It is at rest and from t=0 onwards it is subjected to a time-dependent force in the x- direction. The force varies with t as shown in the figure. The kinetic energy of the block after 4.5 seconds is

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### The resultant of two forces, one double the other in magnitude, is perpendicular to the smaller of the two forces. The angle between the two forces is -

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