Physics-
General
Easy

Question

A current I enters a circular coil of radius R, branches into two parts and then recombines as shown in the circuit diagram

The resultant magnetic field at the centre of the coil is

  1. Zero    
  2. fraction numerator mu subscript 0 end subscript I over denominator 2 R end fraction    
  3. fraction numerator 3 over denominator 4 end fraction open parentheses fraction numerator mu subscript 0 end subscript I over denominator 2 R end fraction close parentheses    
  4. fraction numerator 1 over denominator 4 end fraction open parentheses fraction numerator mu subscript 0 end subscript I over denominator 2 R end fraction close parentheses    

The correct answer is: Zero


    Magnetic field a B
    B subscript 1 end subscript equals fraction numerator mu subscript 0 end subscript over denominator 2 pi end fraction fraction numerator i increment l over denominator r end fraction
    Magnetic field at A
    B subscript 2 end subscript equals fraction numerator mu subscript 0 end subscript over denominator 2 pi end fraction fraction numerator i increment l over denominator r end fraction
    The resultant magnetic field at the centre
    open vertical bar B subscript A end subscript close vertical bar equals open vertical bar B subscript B end subscript close vertical bar
    So, magnetic field become is zero.

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