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Question

If Young’s modulus of elasticity Y for a material is one and half times its rigidity coefficient eta comma the Poisson’s ratio sigma will be

  1. plus fraction numerator 2 over denominator 3 end fraction    
  2. negative fraction numerator 1 over denominator 4 end fraction    
  3. plus fraction numerator 1 over denominator 4 end fraction    
  4. negative fraction numerator 2 over denominator 3 end fraction    

The correct answer is: negative fraction numerator 1 over denominator 4 end fraction


    Young’s modulus, Y equals fraction numerator 3 ɳ over denominator 2 end fraction
    We know that Y equals 2 ɳ open parentheses 1 plus sigma close parentheses
    therefore blank fraction numerator 3 ɳ over denominator 2 end fraction equals 2 ɳ open parentheses 1 plus sigma close parentheses
    blank sigma equals negative fraction numerator 1 over denominator 4 end fraction

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